Question

这是我实验室要求我做的事情。

根据以下要求在Date.java文件中编写类Date：

1）实例变量：月，日，年 - 所有都是type，int，都是私有的

2）构造者：只有一个接受三个整数：月，日和年（按此顺序 - 如果三个参数不形成一致，则抛出异常IllegalArgumentException 日期对象，即无效日期。无效日期可能是： •月份，日期或年份小于1 •一个月大于12 •第1,3,5,7,8,10,12个月的日期大于31 •第4,6,9,11个月的日期超过30天 •在非闰年中，2月份的日期超过28天 •闰年2月份的日期超过29天注意：如果它可以被4整除而不是100，那么一年是飞跃，除非它也可以被400整除例如，1900年没有飞跃，但2000年是飞跃。

3）全套访问者和变异者： •int getMonth（），int getDay，int getYear（） •void setMonth（int m），void setDay（int d），void setYear（int y） - 如果mutator会使Date对象不一致（无效），

应抛出异常IllegalArgumentException

4）方法toString，返回一个显示表单中日期的字符串：MMM-DD-YYYY 示例：JAN-07-2011 NOV-26-2014 FEB-29-2012 JUN-04-1992

5）未指定，但需要：您可能需要一些私有方法来帮助验证部分内容日期和确定一年是否飞跃。

这是实验室13的代码。

public class Lab13 {
public static void main(String[] args) {
   Date d1 =  new Date( 11, 24, 2013 );
   String dateStr = "" + d1;
   if (!dateStr.equals("NOV-24-2013"))
      System.out.println( "ERROR: toString not returning NOV-24-2013 but instead: " + dateStr );

   if ( d1.getMonth() != Date.NOV )
      System.out.println( "ERROR: getMonth not returning NOV but instead: " + d1.getMonth() );

   if ( d1.getDay() != 24 )
      System.out.println( "ERROR: getDay not returning 24 but instead: " + d1.getDay() );

   if ( d1.getYear() != 2013 )
      System.out.println( "ERROR: getYear not returning 2013 but instead: " + d1.getYear() );

   d1.setMonth(12);
   d1.setDay(25);
   d1.setYear(2014);
   dateStr = ""+d1;
   if (!dateStr.equals("DEC-25-2014"))
      System.out.println( "ERROR: mutators(or toString) not returning DEC-25-2014 but instead: " + dateStr );

   try {       
      d1 = new Date( 2, 29, 2016 );
   } catch( IllegalArgumentException iae ) {
      System.out.println( "ERROR: Could not set Date to 2/29/2016" );
   }

   try {       
      d1 = new Date( 2, 29, 2000 );
   } catch( IllegalArgumentException iae ) {
      System.out.println( "ERROR: Could not set Date to 2/29/2000" );
   }

   // trying errors:
   Date d2 = null;

   try {
      d2 = new Date( 13, 14, 2015 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for month = 13" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 0, 14, 2015 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for month = 0" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 1, 32, 2015 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 32 in JAN" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 2, 30, 2016 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 30 in Leap FEB" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 2, 29, 1900 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 29 in non-Leap FEB" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 2, 29, 2014 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 29 in non-Leap FEB" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 4, 31, 2015 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 31 in APR" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 8, 0, 2012 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for day = 0" );
   } catch( IllegalArgumentException iae ) {}

   try {
      d2 = new Date( 8, 15, 0 );
      System.out.println( "ERROR: SHOULD HAVE thrown exception for year = 0" );
   } catch( IllegalArgumentException iae ) {}

   System.out.println("No output above means GREAT Date class!!");
}

}

这是我到目前为止为Date.java编写的代码

public class Date {
private int month;
private int day;
private int year;
public static void check (){
  int m = getMonth(m);
  int y = getYear(y);
  int d = getDay(d);
}
public static void getMonth(int m){
  if (m >= 1 && m <= 12) {
     m = month;
  } else {
    throw IllegalArgumentException("Date not between 1 and 12");
  }
}
public static void getYear(int y) {
  if (y >= 1) {
     y = year;
  } else { 
     throw IllegalArgumentException("Year can not be less than 1");
  }
}
public static void getDay (int d) {
  if (d >= 1 && day <= 31 ) {
     d = day;
  }else if (d < 30 && month == 4|| month == 6 || month == 9 || month == 11) {
     throw IllegalArgumentException("day can not be greater than 30");
  }else if (d < 28 && month == 2 && (year % 4 == 0) && (year % 100 == 0) && (year % 400 != 0) ||
        (year % 4 != 0) && (year % 100 != 0) && (year % 400 != 0)) {
     throw IllegalArgumentException("February can not have over 28 days in non leap year");
  }else if ( d < 29 && month == 2 && (year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0)) {
     throw IllegalArgumentException("February can not have over 29 days in a leap year");
  }
}
}

我遇到的问题是我的实例变量，并试图让他们接受实验室13课程中的数字。当然，如果有人能指出我做错的其他事情，特别是如何找到正确的日子，这将是伟大的。我经常向老师询问这些问题，而且大部分时间他都会回到我这里，但已经过了3天，我真的需要一些帮助。

使用面向对象编程检查日期

0 个答案: