Question

我有以下表格：

学生

Student_Course

场

现在，当我创建学生时，我只想创建一个用户并向student_course添加一行。我遇到的“问题”是，当我在Student中设置课程集合为cascade =“save-update”时，也会在课程中调用更新。我想知道是否有办法阻止这种情况。

Answer 1

如果确实需要这种行为，则应将@ManyToMany关系拆分为@ OneToMany-ManyToOne关系

obs：别忘了实施setter的

public class Student {

    private Integer id;

    public Set<StudentCourse> studentCourseSet = new HashSet<StudentCourse>();

    @Id
    @GeneratedValue
    public Integer getId() {
        return this.id;
    }

    /**
      * Because you are using a Set collection
      * You must provide equals and hashcode implementation in StudentCourse class
      */
    @OneToMany(cascade=CascadeType.ALL)
    @JoinColumn(name="STUDENT_ID", insertable=false, updatable=false)
    public Set<StudentCourse> getStudentCourseSet() {
        return this.studentCourseSet;
    }

    /**
      * add convenience method
      */
    public void addCourse(Course course) {
        getStudentCourseSet().add(new StudentCourseId(getId(), course.getId()));
    }

    /**
      * Feel free to implement your StudentCourse class outside Student one
      */   
    @Entity
    @Table(name="<TABLE_NAME_GOES_HERE>")
    public static class StudentCourse {

        private StudentCourseId studentCourseId;

        public Student student;
        public Course course;

        /**
          * required no-arg constructor
          */
        public StudentCourse() {}

        public StudentCourse(StudentCourseId studentCourseId) {
            this.studentCourseId = studentCourseId;
        }

        @EmbeddedId
        public StudentCourseId getStudentCourseId() {
            return this.studentCourseId;
        }

        @ManyToOne(fetch=FetchType.LAZY)
        @JoinColumn(name="STUDENT_ID", insertable=false, updatable=false)
        public Student getStudent() { 
            return this.student;
        }

        @ManyToOne(fetch=FetchType.LAZY)
        @JoinColumn(name="COURSE_ID", insertable=false, updatable=false)
        public Course getCourse() { 
            return this.course;
        }

        @Embeddable
        public static class StudentCourseId implements Serializable {

            private Integer studentId;
            private Integer courseId;

            /**
              * required no-arg constructor
              */
            public StudentCourseId() {}

            public StudentCourseId(Integer studentId, Integer courseId) {
                this.studentId = studentId;
                this.courseId = courseId;
            }

            @Column(name="STUDENT_ID", nullable=false)
            public Integer getStudentId() {
                return this.studentId;
            }

            @Column(name="COURSE_ID", nullable=false)
            public Integer getCourseId() {
                return this.courseId;
            }

            // required equals and hashcode
            public boolean equals(Object o) {
                if(o == null)
                    return false;

                if(!(o instanfeof StudentCourseId))
                    return false;

                StudentCourseId other = (StudentCourseId) o;
                if(!(getStudentId().equals(o.getStudentId())))
                    return false;

                if(!(getCourseId().equals(o.getCourseId())))
                    return false;

                return false;
            }

            public int hashcode() {
                // hashcode impl goes here
            }

        }

    }

}

hibernate许多对很多只保存新对象和表之间

1 个答案: