Question

我有两个约会（01/01/2012，2014年7月31日）。

请你帮我计算这两个日期之间的月差。如果差异是8个月1天我需要结果9个月。

Answer 1

Working Code:

public int monthsBetweenDates(Date startDate, Date endDate){

        Calendar start = Calendar.getInstance();
        start.setTime(startDate);

        Calendar end = Calendar.getInstance();
        end.setTime(endDate);

          int monthsBetween = 0;
            int dateDiff = end.get(Calendar.DAY_OF_MONTH)-start.get(Calendar.DAY_OF_MONTH);      

if(dateDiff<0) {
                int borrrow = end.getActualMaximum(Calendar.DAY_OF_MONTH);           
                 dateDiff = (end.get(Calendar.DAY_OF_MONTH)+borrrow)-start.get(Calendar.DAY_OF_MONTH);
                 monthsBetween--;

if(dateDiff>0) {
                     monthsBetween++;
                 }
            }
            else {
                monthsBetween++;
            }      
            monthsBetween += end.get(Calendar.MONTH)-start.get(Calendar.MONTH);      
            monthsBetween  += (end.get(Calendar.YEAR)-start.get(Calendar.YEAR))*12;      
            return monthsBetween;
     }

Answer 2

您可以使用Calendar之类的

static int monthsBetween(Date a, Date b) {
    Calendar cal = Calendar.getInstance();
    if (a.before(b)) {
        cal.setTime(a);
    } else {
        cal.setTime(b);
        b = a;
    }
    int c = 0;
    while (cal.getTime().before(b)) {
        cal.add(Calendar.MONTH, 1);
        c++;
    }
    return c - 1;
}

然后你可以称之为

public static void main(String[] args) {
    String start = "01/01/2012";
    String end = "31/07/2014";
    DateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
    try {
        System.out.println(monthsBetween(sdf.parse(start), sdf.parse(end)));
    } catch (ParseException e) {
        e.printStackTrace();
    }
}

输出

或者，使用Joda-Time

String start = "01/01/2012";
String end = "31/07/2014";
DateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try {
    LocalDate a = LocalDate.fromDateFields(sdf.parse(start));
    LocalDate b = LocalDate.fromDateFields(sdf.parse(end));
    Period p = new Period(a, b);
    System.out.println((p.getYears() * 12) + p.getMonths());
} catch (ParseException e) {
    e.printStackTrace();
}

输出也是

修改

最后（如评论中所述），如果您使用的是Java 8，则可以使用新的java.time类，如

String start = "01/01/2012"; String end = "31/07/2014"; DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd/MM/yyyy"); LocalDate from = LocalDate.parse(start, formatter); LocalDate to = LocalDate.parse(end, formatter); System.out.println(from.until(to, ChronoUnit.MONTHS));

输出是（仍然）

30

Answer 3

我的代码：

int getMonthCountBetween(Calendar cal1, Calendar cal2) {

        if(cal1.compareTo(cal2)>0) {
            Calendar cal=cal1;
            cal1=cal2;
            cal2=cal;
        }

        int months=0;

        int y1 = cal1.get(Calendar.YEAR);
        int y2 = cal2.get(Calendar.YEAR);

        int m1 = cal1.get(Calendar.MONTH);
        int m2 = cal2.get(Calendar.MONTH);

        if (y2 - y1 >= 0) {
            months = m2 - m1 + 1;
        }
        if (y2 - y1 >= 1) {
            months += 12;
        }
        if (y2 - y1 >= 2) {
            months += 12 * (y2 - y1 - 1);
        }

        return months;
    }

Answer 4

int months = 12*(toYear-fromYear)+(toMonth-fromMonth)+(toDay>=fromDay?1:0)

哪里是以后的日期，从哪里是以前的日期

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4 个答案: