我在数据库中有一个开始日期和结束日期,如下所示。
开始日期:2014年6月1日结束日期:2014年6月30日
开始日期:2014年7月1日结束日期:2014年9月30日
开始日期:2014年10月1日结束日期:2015年3月31日
如果我输入日期范围
开始日期02/06/2014
结束日期01/02/2015
输出必须是。
28 days, in 1st slab date range
2 months, 29 days, in 2nd slab date range
4 months in 3rd slab date range
如何在java中实现这一点。
提前致谢。
答案 0 :(得分:1)
这个问题很难准确回答。我相信这就是你真正想要的,
// get the minimum of any number of dates.
private static Date getMinimum(Date... dates) {
if (dates == null)
return null;
Date min = dates[0];
for (Date d : dates) {
if (d.compareTo(min) < 0) {
min = d;
}
}
return min;
}
// get the maximum of any number of dates.
private static Date getMaximum(Date... dates) {
if (dates == null)
return null;
Date max = dates[0];
for (Date d : dates) {
if (d.compareTo(max) > 0) {
max = d;
}
}
return max;
}
public static String getDateDiff(Date startDate,
Date endDate) {
StringBuilder sb = new StringBuilder();
Calendar start = Calendar.getInstance();
start.setTime(getMinimum(startDate, endDate));
Calendar end = Calendar.getInstance();
end.setTime(getMaximum(startDate, endDate));
if (start.compareTo(end) < 0) {
int monthCount = 0;
int dayCount = 0;
while (start.compareTo(end) < 0) {
start.add(Calendar.MONTH, 1);
if (start.compareTo(end) < 0) {
monthCount++;
}
}
start = Calendar.getInstance();
start.setTime(getMinimum(startDate, endDate));
start.add(Calendar.MONTH, monthCount);
while (start.compareTo(end) < 0) {
start.add(Calendar.DAY_OF_MONTH, 1);
if (start.compareTo(end) < 0) {
dayCount++;
}
}
if (monthCount > 0) {
sb.append(String.format("%d months",
monthCount));
}
if (dayCount > 0) {
if (sb.length() > 0) {
sb.append(", ");
}
sb.append(String.format("%d days", dayCount));
}
} else {
sb.append("0 days");
}
return sb.toString();
}
public static void main(String[] args) {
String[] input = { "01/06/2014-30/06/2014", //
"01/07/2014-30/09/2014", //
"01/10/2014-31/03/2015", //
"02/06/2014-01/02/2015", };
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
for (String str : input) {
String sArr[] = str.split("-");
try {
Date start = df.parse(sArr[0]);
Date end = df.parse(sArr[1]);
System.out.printf("start: %s, end: %s - diff: %s\n", sArr[0],
sArr[1], getDateDiff(start, end));
} catch (ParseException e) {
e.printStackTrace();
}
}
}
输出
start: 01/06/2014, end: 30/06/2014 - diff: 28 days
start: 01/07/2014, end: 30/09/2014 - diff: 2 months, 28 days
start: 01/10/2014, end: 31/03/2015 - diff: 5 months, 29 days
start: 02/06/2014, end: 01/02/2015 - diff: 7 months, 29 days
答案 1 :(得分:0)
Please check whether below code is helpful. I am using this.
public String getDifference(Date date1, Date date2){
long difference = date2.getTime() - date1.getTime();
long diffDays = difference / (24 * 60 * 60 * 1000);
return (diffDays/30)+" months and "+(diffDays%30)+" days";
}
答案 2 :(得分:0)
public int monthsBetweenDates(Date startDate, Date endDate){
Calendar start = Calendar.getInstance();
start.setTime(startDate);
Calendar end = Calendar.getInstance();
end.setTime(endDate);
int monthsBetween = 0;
int dateDiff = end.get(Calendar.DAY_OF_MONTH)-start.get(Calendar.DAY_OF_MONTH);
if(dateDiff<0) {
int borrrow = end.getActualMaximum(Calendar.DAY_OF_MONTH);
dateDiff = (end.get(Calendar.DAY_OF_MONTH)+borrrow)-start.get(Calendar.DAY_OF_MONTH);
monthsBetween--;
if(dateDiff>0) {
monthsBetween++;
}
}
else {
monthsBetween++;
}
monthsBetween += end.get(Calendar.MONTH)-start.get(Calendar.MONTH);
monthsBetween += (end.get(Calendar.YEAR)-start.get(Calendar.YEAR))*12;
return monthsBetween;
}