我见过这个Issue while building dynamic Expression Tree和Expression/Statement trees因为我是表达树的新手,所以我仍然在努力去理解如何实现我想要的目标。
下面有一个人为的对象
public class TestObject
{
public TestObject()
{
ClassList = new List<Class>();
}
public int Age { get; set; }
public List<Class> ClassList { get; set; }
}
public class Class
{
public string Name { get; set; }
public int ClassId { get; set; }
}
在运行时,我遍历每个属性并生成一个Delegate,它转换为该属性的字符串。我已经完成了所有工作。我现在必须处理的问题是,对于List类型,我需要能够对ClassList属性中的每个项应用一组动作,所以我需要一个foreach来允许我这样做。
我目前有这个
//type==TestObject at runtime
//propertyName == "ClassList"
ParameterExpression recordExpression = Expression.Parameter(type, "record");
memberExpression = MemberExpression.Property(recordExpression, propertyName);
Type getEnumerableDelegateType =
typeof(Func<,>).MakeGenericType(new Type[] { type, memberExpression.Type});
var getList = Expression.Lambda(getEnumerableDelegateType, memberExpression, recordExpression);
编译和调用时,GetList按预期返回List。我正在努力的是如何创建一个表达式,它将使用lambda表达式的结果并使用我已为每个Class项创建的一组动作迭代它。
最终我正在寻找符合下面 overallAction 签名的lambda签名
var getListFunc = new Func<TestObject, List<Class>>((TestObject obj1) => obj1.ClassList);
Action<List<Class>> listAction = delegate(List<Class> data)
{
foreach (var dataChannelWithUnitse in data)
{
//Apply generated delegate
}
};
Action<TestObject> overallAction = delegate(TestObject data)
{
var x = getListFunc.Invoke(data);
listAction.Invoke(x as List<Class>);
};
感谢任何帮助,以帮助我了解如何执行此操作。
我目前得到的这个例外是变量'输入',类型'TestObject'从范围''引用,但它没有定义
var typeParam = Expression.Parameter(type, "Input");
var listVariable = Expression.Variable(memberExpression.Type, "List");
var enumerator = Expression.Variable(typeof(IEnumerator<>).MakeGenericType(dataType));
var enumeratorType = typeof(IEnumerator<>).MakeGenericType(dataType);
var enumerableType = typeof(IEnumerable<>).MakeGenericType(dataType);
var enumerableParam = Expression.Parameter(enumerableType, "ExtractedCollection");
var getEnumeratorFunc = Expression.Call(enumerableParam, enumerableType.GetMethod("GetEnumerator"));
var getEnumeratorLambda = Expression.Lambda(getEnumeratorFunc, enumerableParam);
var t1 = Expression.Assign(listVariable, Expression.Invoke(getListLambda, typeParam));
var t2 = Expression.Assign(enumerator, Expression.Invoke(getEnumeratorLambda, listVariable));
var @break = Expression.Label();
var funcBlock = Expression.Block(
new ParameterExpression[] { listVariable, enumerator},
t1,
t2,
Expression.Loop(
Expression.IfThenElse(
Expression.NotEqual(Expression.Call(enumerator,typeof(IEnumerator).GetMethod("MoveNext")),Expression.Constant(false)),
Expression.Invoke(enumerableExpressions[0],Expression.Property(enumerator, "Current")),
Expression.Break(@break))
, @break), typeParam);
Expression<Action<TestObject>> lm = Expression.Lambda<Action<TestObject>>(funcBlock,recordExpression);
var d = lm.Compile(); **//this is exceptioning with " variable 'Input' of type 'TestObject' referenced from scope '', but it is not defined**
答案 0 :(得分:18)
我在你问题的中间某处迷路了(如果我对它的解释不正确,请告诉我,我会重新考虑它),但我想这就是你所追求的:
public static Expression ForEach(Expression collection, ParameterExpression loopVar, Expression loopContent)
{
var elementType = loopVar.Type;
var enumerableType = typeof(IEnumerable<>).MakeGenericType(elementType);
var enumeratorType = typeof(IEnumerator<>).MakeGenericType(elementType);
var enumeratorVar = Expression.Variable(enumeratorType, "enumerator");
var getEnumeratorCall = Expression.Call(collection, enumerableType.GetMethod("GetEnumerator"));
var enumeratorAssign = Expression.Assign(enumeratorVar, getEnumeratorCall);
// The MoveNext method's actually on IEnumerator, not IEnumerator<T>
var moveNextCall = Expression.Call(enumeratorVar, typeof(IEnumerator).GetMethod("MoveNext"));
var breakLabel = Expression.Label("LoopBreak");
var loop = Expression.Block(new[] { enumeratorVar },
enumeratorAssign,
Expression.Loop(
Expression.IfThenElse(
Expression.Equal(moveNextCall, Expression.Constant(true)),
Expression.Block(new[] { loopVar },
Expression.Assign(loopVar, Expression.Property(enumeratorVar, "Current")),
loopContent
),
Expression.Break(breakLabel)
),
breakLabel)
);
return loop;
}
要使用它,您需要提供一个迭代的集合,一个替换为循环体的表达式,以及一个循环体表达式使用的ParameterExpression,它将被分配给每个循环变量。循环迭代。
我认为有时候例子比言辞更响亮......
var collection = Expression.Parameter(typeof(List<string>), "collection");
var loopVar = Expression.Parameter(typeof(string), "loopVar");
var loopBody = Expression.Call(typeof(Console).GetMethod("WriteLine", new[] { typeof(string) }), loopVar);
var loop = ForEach(collection, loopVar, loopBody);
var compiled = Expression.Lambda<Action<List<string>>>(loop, collection).Compile();
compiled(new List<string>() { "a", "b", "c" });
编辑:正如Jeroem Mostert在评论中正确指出的那样,这并没有完全反映出真实的&#34; foreach循环的行为:这将确保它处理枚举器。 (它还会为每次迭代创建一个新的循环变量实例,但这对表达式没有意义)。如果你觉得有足够的动力,那么实现这个只是一个问题!
对于在家观看的任何人,我都有类似的方法来生成&#39;循环:
public static Expression For(ParameterExpression loopVar, Expression initValue, Expression condition, Expression increment, Expression loopContent)
{
var initAssign = Expression.Assign(loopVar, initValue);
var breakLabel = Expression.Label("LoopBreak");
var loop = Expression.Block(new[] { loopVar },
initAssign,
Expression.Loop(
Expression.IfThenElse(
condition,
Expression.Block(
loopContent,
increment
),
Expression.Break(breakLabel)
),
breakLabel)
);
return loop;
}
这相当于以下语句,其中伪变量与上述方法中的表达式匹配:
for (loopVar = initValue; condition; increment)
{
loopContent
}
同样,loopContent,condition和increment是使用loopVar的表达式,并且在每次迭代时都会分配loopVar。
答案 1 :(得分:2)
以下是canton7's excellent solution的略微扩展版本,其中考虑到有关设置枚举器的注意事项:
public static Expression ForEach(Expression enumerable, ParameterExpression loopVar, Expression loopContent)
{
var elementType = loopVar.Type;
var enumerableType = typeof(IEnumerable<>).MakeGenericType(elementType);
var enumeratorType = typeof(IEnumerator<>).MakeGenericType(elementType);
var enumeratorVar = Expression.Variable(enumeratorType, "enumerator");
var getEnumeratorCall = Expression.Call(enumerable, enumerableType.GetMethod("GetEnumerator"));
var enumeratorAssign = Expression.Assign(enumeratorVar, getEnumeratorCall);
var enumeratorDispose = Expression.Call(enumeratorVar, typeof(IDisposable).GetMethod("Dispose"));
// The MoveNext method's actually on IEnumerator, not IEnumerator<T>
var moveNextCall = Expression.Call(enumeratorVar, typeof(IEnumerator).GetMethod("MoveNext"));
var breakLabel = Expression.Label("LoopBreak");
var trueConstant = Expression.Constant(true);
var loop =
Expression.Loop(
Expression.IfThenElse(
Expression.Equal(moveNextCall, trueConstant),
Expression.Block(
new[] { loopVar },
Expression.Assign(loopVar, Expression.Property(enumeratorVar, "Current")),
loopContent),
Expression.Break(breakLabel)),
breakLabel);
var tryFinally =
Expression.TryFinally(
loop,
enumeratorDispose);
var body =
Expression.Block(
new[] { enumeratorVar },
enumeratorAssign,
tryFinally);
return body;
}
答案 2 :(得分:1)
relatively_random's solution很不错,但是foreach
处理其他几种情况。检查指向SharpLab的以下链接,以验证每个链接中生成的内容:
IEnumerable<T>
时,它将在调用null
之前检查枚举数是否为Dispose()
。GetEnumerator()
返回的类型。调用IDisposable
之前,将枚举数强制转换为Dispose()
。IDisposable
时,将使用as
来检查枚举数是否实现了IDisposable
。 (???)null
的支票消失了。IDisposable
时,try
/ finally
消失。使用GetEnumerator()
返回的类型非常重要,这样就不会对值类型枚举器进行装箱。 System.Collections.Generic
中的所有集合都具有值类型的枚举器,因为对其方法的调用不是虚拟的,从而提高了性能。
将所有内容放在一起将产生以下代码:
static partial class ExpressionEx
{
public static Expression ForEach<TSource>(Expression enumerable, Expression loopContent)
{
var enumerableType = enumerable.Type;
var getEnumerator = enumerableType.GetMethod("GetEnumerator");
if (getEnumerator is null)
getEnumerator = typeof(IEnumerable<>).MakeGenericType(typeof(TSource)).GetMethod("GetEnumerator");
var enumeratorType = getEnumerator.ReturnType;
var enumerator = Expression.Variable(enumeratorType, "enumerator");
return Expression.Block(new[] { enumerator },
Expression.Assign(enumerator, Expression.Call(enumerable, getEnumerator)),
EnumerationLoop(enumerator, loopContent));
}
public static Expression ForEach<TSource>(Expression enumerable, ParameterExpression loopVar, Expression loopContent)
{
var enumerableType = enumerable.Type;
var getEnumerator = enumerableType.GetMethod("GetEnumerator");
if (getEnumerator is null)
getEnumerator = typeof(IEnumerable<>).MakeGenericType(typeof(TSource)).GetMethod("GetEnumerator");
var enumeratorType = getEnumerator.ReturnType;
var enumerator = Expression.Variable(enumeratorType, "enumerator");
return Expression.Block(new[] { enumerator },
Expression.Assign(enumerator, Expression.Call(enumerable, getEnumerator)),
EnumerationLoop(enumerator,
Expression.Block(new[] { loopVar },
Expression.Assign(loopVar, Expression.Property(enumerator, "Current")),
loopContent)));
}
static Expression EnumerationLoop(ParameterExpression enumerator, Expression loopContent)
{
var loop = While(
Expression.Call(enumerator, typeof(IEnumerator).GetMethod("MoveNext")),
loopContent);
var enumeratorType = enumerator.Type;
if (typeof(IDisposable).IsAssignableFrom(enumeratorType))
return Using(enumerator, loop);
if (!enumeratorType.IsValueType)
{
var disposable = Expression.Variable(typeof(IDisposable), "disposable");
return Expression.TryFinally(
loop,
Expression.Block(new[] { disposable },
Expression.Assign(disposable, Expression.TypeAs(enumerator, typeof(IDisposable))),
Expression.IfThen(
Expression.NotEqual(disposable, Expression.Constant(null)),
Expression.Call(disposable, typeof(IDisposable).GetMethod("Dispose")))));
}
return loop;
}
public static Expression Using(ParameterExpression variable, Expression content)
{
var variableType = variable.Type;
if (!typeof(IDisposable).IsAssignableFrom(variableType))
throw new Exception($"'{variableType.FullName}': type used in a using statement must be implicitly convertible to 'System.IDisposable'");
var getMethod = typeof(IDisposable).GetMethod("Dispose");
if (variableType.IsValueType)
{
return Expression.TryFinally(
content,
Expression.Call(Expression.Convert(variable, typeof(IDisposable)), getMethod));
}
if (variableType.IsInterface)
{
return Expression.TryFinally(
content,
Expression.IfThen(
Expression.NotEqual(variable, Expression.Constant(null)),
Expression.Call(variable, getMethod)));
}
return Expression.TryFinally(
content,
Expression.IfThen(
Expression.NotEqual(variable, Expression.Constant(null)),
Expression.Call(Expression.Convert(variable, typeof(IDisposable)), getMethod)));
}
public static Expression While(Expression loopCondition, Expression loopContent)
{
var breakLabel = Expression.Label();
return Expression.Loop(
Expression.IfThenElse(
loopCondition,
loopContent,
Expression.Break(breakLabel)),
breakLabel);
}
}
没有ForEach
的{{1}}可以用于枚举而不获取项目。 loopVar
的实现就是这种情况。