async
Task
的调度不能像我在TPL Dataflow中预期的那样工作。在下面的示例中,我希望ActionBlock
在TransformBlock
可用时立即处理数据。但它正在等待第二个(延迟)结果,然后才进入第三个结果。我在这里误解了什么?处理顺序是否有一些要求?
public class TestDataFlow
{
public System.Diagnostics.Stopwatch watch = new System.Diagnostics.Stopwatch();
public async Task Flow()
{
watch.Start();
var plus10 = new TransformBlock<int, int>(async input =>
{
if (input == 2)
{
await Task.Delay(5000);
}
Console.WriteLine("Exiting plus10 for input {0} @ {1}", input, watch.Elapsed);
return input + 10;
},
new ExecutionDataflowBlockOptions
{
MaxDegreeOfParallelism = 4,
});
var printSolution = new ActionBlock<int>(input =>
{
Console.WriteLine("Solution: {0} @ {1}", input, watch.Elapsed.TotalMilliSeconds);
},
new ExecutionDataflowBlockOptions
{
MaxDegreeOfParallelism = 4,
});
plus10.LinkTo(printSolution);
List<int> inputs = new List<int> { 1, 2, 3 };
foreach (var input in inputs)
{
await plus10.SendAsync(input);
}
}
}
输出:
Exiting plus10 for input 1 @ 115.8583
Exiting plus10 for input 3 @ 116.6973
Solution: 11 @ 126.0146
Exiting plus10 for input 2 @ 5124.4074
Solution: 12 @ 5124.9014
Solution: 13 @ 5126.4834
答案 0 :(得分:5)
TPL Dataflow保证输入和输出队列的顺序,无论并行处理多少项。
&#34;因为每个预定义的源数据流块类型都保证消息按接收顺序传播出去,所以必须在源块处理下一个消息之前从源块读取每条消息。
来自Dataflow (Task Parallel Library)
如果您希望项目在完成处理时准确转移到下一个区块,则应自行明确转移这些项目,这会将您的TransformBlock
变为ActionBlock
:
var printSolution = new ActionBlock<int>(input =>
{
Console.WriteLine("Solution: {0} @ {1}", input, watch.Elapsed.TotalMilliSeconds);
},executionDataflowBlockOptions);
var plus10 = new ActionBlock<int>(async input =>
{
if (input == 2)
{
await Task.Delay(5000);
}
Console.WriteLine("Exiting plus10 for input {0} @ {1}", input, watch.Elapsed);
await printSolution.SendAsync(input + 10);
}, executionDataflowBlockOptions);
答案 1 :(得分:2)
截至(至少)System.Threading.Tasks.Dataflow.4.6.0
,ExecutionDataflowBlockOptions
现在有一个属性EnsureOrdered
,可以设置为false
。
更新:
Install-Package System.Threading.Tasks.Dataflow
代码:
var options = new ExecutionDataflowBlockOptions {
EnsureOrdered = false
};
var transform = new TransformBlock<int, int>(i => Transform(i), options);
更多示例:https://stackoverflow.com/a/38865414/625919
发展历史,我认为它很整洁:https://github.com/dotnet/corefx/issues/536 https://github.com/dotnet/corefx/pull/5191