Question

我开始在JPA 2.1中使用新的实体图形功能来指定必须加载的Lazy集合。考虑以下课程：

@Entity
@NamedQueries({
    @NamedQuery(name="findWithFilterAttr","select a from A a where a.filterAttribute like :filter")
})
@NamedEntityGraphs({
@NamedEntityGraph(name = "graph.childs", attributeNodes = @NamedAttributeNode("childs"))})
public class A{
  @Id
  private long id;
  @OneToMany(mappedBy="parent")
  private List<B> childs;
  private String filterAttribute;
}
@Entity
public class B{ 
  @Id
  private long id;
  @ManyToOne
  private A parent;
}

当我执行命名查询以获取具有实体图提示的A实体列表时，我得到一个带有重复A实体的集合。如何只加载A实体一次。

我正在使用：

Hibernate 4.3.5
Wildfly 8.1

Answer 1

我终于解决了这个问题，我在命名查询中添加了DISTINCT，现在一切正常.... 导致该错误是因为当JPA Provider找到实体图提示时，它会创建一个带子表的LEFT JOIN。没有实体图的原始查询：

11:55:28,950 INFO  [stdout] (default task-23) Hibernate: 
11:55:28,950 INFO  [stdout] (default task-23)     select
11:55:28,951 INFO  [stdout] (default task-23)         entitya0_.id as id1_0_0_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.id as id1_1_1_,
11:55:28,951 INFO  [stdout] (default task-23)         entitya0_.filter as filter2_0_0_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.parent_id as parent_i2_1_1_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.parent_id as parent_i2_0_0__,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.id as id1_1_0__ 
11:55:28,951 INFO  [stdout] (default task-23)     from
11:55:28,951 INFO  [stdout] (default task-23)         EntityA entitya0_ 
11:55:28,951 INFO  [stdout] (default task-23)     left outer join
11:55:28,952 INFO  [stdout] (default task-23)         EntityB childs1_ 
11:55:28,952 INFO  [stdout] (default task-23)             on entitya0_.id=childs1_.parent_id 
11:55:28,952 INFO  [stdout] (default task-23)     where
11:55:28,952 INFO  [stdout] (default task-23)         entitya0_.filter like ?

使用distinct和entity graph进行查询：

11:57:25,051 INFO  [stdout] (default task-24) Hibernate: 
11:57:25,052 INFO  [stdout] (default task-24)     select
11:57:25,052 INFO  [stdout] (default task-24)         distinct entitya0_.id as id1_0_0_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.id as id1_1_1_,
11:57:25,052 INFO  [stdout] (default task-24)         entitya0_.filter as filter2_0_0_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.parent_id as parent_i2_1_1_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.parent_id as parent_i2_0_0__,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.id as id1_1_0__ 
11:57:25,052 INFO  [stdout] (default task-24)     from
11:57:25,052 INFO  [stdout] (default task-24)         EntityA entitya0_ 
11:57:25,052 INFO  [stdout] (default task-24)     left outer join
11:57:25,052 INFO  [stdout] (default task-24)         EntityB childs1_ 
11:57:25,052 INFO  [stdout] (default task-24)             on entitya0_.id=childs1_.parent_id 
11:57:25,052 INFO  [stdout] (default task-24)     where
11:57:25,052 INFO  [stdout] (default task-24)         entitya0_.filter like ?

Answer 2

一个小补充。

我和你有同样的问题。我认为这种行为是出乎意料的，可能是休眠的一个缺陷。不应该指定distinct，因为它是JPQL查询中直接指定的提取的情况。

由于实施的限制，您的解决方案是一种解决方法。通过检查代码（方法needsDistincting中的list()标志的计算，grepcode处可用），有2个解决方案：

为查询添加限制
使用distinct

JPA 2.1实体图表返回重复的结果

2 个答案: