Question

假设我有以下实体：

@Entity
@Table (name = "customers)
public class CustomerImpl implements Customer {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", nullable = false, unique = true)
private Long id;

@Column(name = "name", nullable = false)
private String name;

@Column(name = "surname", nullable = false)
private String surname;

@Column(name = "country", nullable = false)
private String country;

@Column(name = "city", nullable = false)
private String city;

@Column(name = "street", nullable = false)
private String street;

@Column(name = "zipCode", nullable = false)
private String zipCode;

// constructor + getters

}

我想创建一个名为地址的新类，它将包含国家，街道，城市和邮政编码变量。然后，概述的变量将替换为Address对象，以使代码更易读和更清晰。

在我的情况下，应该嵌入Address类还是应该将其指定为新实体并在Address和Customer之间给出@OneToOne关系？

谢谢

Answer 1

为了使您的代码更具可读性和清晰度，您应该创建一个包含country，city ...的ADRESSE表，然后您可以使用@OneToOne关系，如下所示：

在Customer类中：

@OneToOne(mappedBy = "customer", fetch = FetchType.LAZY)
private Address address;
// Getter + Setter

在Adresse课程中：

@OneToOne
@JoinColumn(name="id")
private Customer customer;

将JPA实体划分为两个？

1 个答案: