Question

我有来自http://lampload.com/component/option,com_jdownloads/Itemid,382/cid,69/task,view.download/的脚本（我没有使用数据库）我可以上传图片，我可以查看文件，但我想删除它们。当我按下删除按钮时，没有任何反应

http://www.jayg.co.uk/gallery6/upload_gallery.php

<?php
$dir = dirname(__FILENAME__)."/images/gallery" ;
$files1 = scandir($dir);
foreach($files1 as $file){
if(strlen($file) >=3){
$foil = strstr($file, 'jpg'); // As of PHP 5.3.0
$foil = $file;
$pos = strpos($file, 'css');
if ($foil==true){
echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />';
echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host
//echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/      $file' /><br/>";
}
}
}?>
<input type="submit" name="mysubmit2" value="Delete">
</form>

任何想法？

Answer 1

Waw！，你的方式是错误的。为简单起见，为什么不实现数据库在编纂中。无论如何，根据您的要求，我已经开发了此代码以及css文件。它已经过测试，现在正在运行。如果您需要更多帮助，请评价我的回复并给我一个喊叫。 ...... Sectona

index.php
<?php
extract($_REQUEST);
?>
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title></title>

<style>



#box{ width:200px; height:auto; border:solid #999 10px; padding:10px; margin:0 auto; margin-top:100px; background-color:#FFF;-webkit-box-shadow: 0 1px 2px #666;box-shadow: 0 1px 2px #666; color:#66F;}

.link{padding:5px; text-decoration:none; background-color:#333; color:#FFF}

</style>

</head>

<body>


<div id="box">


<img src="images/3.jpg" />

<p></p>

<a href="delete.php?del=1" class="link">Delete</a>

</div>


</body>
</html>



delete.php

<?php
extract($_REQUEST);


unlink("images/3.jpg");

// Redirect to a page that prints image deleted successfully

header("Location:success_delete.php");

?>

显示文件夹中的图像并删除图像

1 个答案: