Question

我想要计算我的邮政编码中每个数字的总和，所以我写了这样的实现函数但是，它显示“0”作为答案，然后我意识到应该先调用，我将correctionDigitOf（）添加到构造函数“Zipcode :: Zipcode“然后我的邮政编码全部为”0“，所以请帮忙！

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <ctime>
#include <cmath>

using namespace std;

class Zipcode
{
public:
    Zipcode();

    void createZipcode();
    int getZipcode();
    int extract(int location);
    int getCoreectionDigit();
    void correctionDigitOf();

private:
    int zipcode;
    int correctionDigit;
};

Zipcode::Zipcode()
{
    zipcode = 0;
    correctionDigit = 0;
    createZipcode();
}

void Zipcode::createZipcode()
{
    zipcode = 10000 + rand() % 99999;
}

int Zipcode::getZipcode()
{
    return zipcode;
}

int Zipcode::extract(int location)
{
    int i = 1;
    while (i<location)
    {

        i++;
        zipcode /= 10;
    }

    return zipcode % 10;
}

void Zipcode::correctionDigitOf()
{
    correctionDigit = extract(1) + extract(2) + extract(3) + extract(4) + extract(5);
}

int Zipcode::getCoreectionDigit()
{

    return correctionDigit;
}

int main()
{
    const int num = 10;

    for (int i = 0; i<num; i++)
    {

        Zipcode zip;
        cout << zip.getZipcode()
            << ' '
            << zip.getCoreectionDigit()
            << endl;

    }

    return 0;
}

Answer 1

您的Zipcode::extract更改了zipcode的值，这可能是您想要的。

计算我的邮政编码中的数字总和

1 个答案: