我的两个数据集是：
fnamerp1=([ 93, 87, 96, 93, 90, 123, 111, 82, 87, 115, 103,
101, 93, 92, 111, 107, 114, 106, 116, 106, 128, 115,
141, 134, 120, 149, 140, 166, 152, 171, 192, 207, 227,
266, 270, 286, 355, 385, 397, 488, 462, 531, 579, 622,
711, 720, 801, 858, 906, 915, 915, 956, 1004, 1012, 1045,
1076, 1063, 1013, 985, 924, 959, 838, 766, 763, 742, 642,
587, 557, 484, 393, 353, 341, 284, 240, 221, 209, 147,
109, 113, 102, 71, 63, 63, 50, 29, 39, 36, 25,
30, 23, 27, 23, 19, 19, 24, 15, 23, 21, 26,
15])
fnamerp2=([ 105, 89, 120, 121, 103, 105, 113, 94, 104, 115, 122, 116, 121,
129, 118, 126, 138, 146, 161, 163, 178, 192, 194, 222, 268, 272,
285, 342, 380, 378, 373, 448, 493, 511, 571, 603, 691, 772, 738,
796, 839, 832, 883, 930, 963, 975, 972, 931, 947, 941, 934, 964,
871, 869, 826, 793, 733, 708, 606, 610, 515, 483, 409, 352, 358,
264, 266, 205, 191, 167, 136, 138, 99, 102, 82, 57, 65, 53,
51, 32, 26, 27, 39, 21, 29, 23, 25, 24, 16, 17, 27,
33, 19, 13, 24, 26, 18, 22, 18, 20])
我想找到两个峰的中心之间的滞后（不仅仅是它们的最大值）。我的计划是使用np.argmax(signal.correlate(fnamerp1,fnamerp2))。
从数学的角度来看，从Python中优雅地做到这一点的正确方法是什么？