C ++将数字转换为类型的指针？

Question

我有以下代码：

int* anInt = new int(5);
uintptr_t memAddr = (uintptr_t)&anInt;
Log("memAddr is: " + std::to_string(memAddr));
int* anotherInt = (int*)&memAddr;
Log("anInt is: " + std::to_string(*anInt));
Log("anotherInt is: " + std::to_string(*anotherInt));

现在我希望anotherInt指向与anInt相同的值，但是当前代码使anotherInt指向memAddr的值。如何将anotherInt设置为仅使用memAddr指向anInt的值？

Answer 1

您可以直接键入一个指针到整数。这将使anotherInt指向与anInt相同的int。

uintptr_t memAddr = (uintptr_t)anInt;
...
int* anotherInt = (int*)memAddr;

或者你可以让memAddr存储指针的地址（一个指向指针的指针）并按原样使用它：

uintptr_t memAddr = (uintptr_t)&anInt;
...
// only works if the variable "anInt" is still alive
int* anotherInt = *(int**)memAddr;