Question

由于某种原因，TicTacToeBoard类中的Move（）函数无法正常工作。

这是主要的：

import java.util.*;

public class TicTakToe {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        System.out.println("What player are you(X or O)?");
        String player = in.next();
        System.out.println("What row do you want to play in(top, middle, bottom)?");
        String row = in.next();
        System.out.println("What column do you want to play in(left, center, right)?");
        String column = in.next();

        System.out.println(player + ", " + row + ", " + column);
        TicTacToeBoard one = new TicTacToeBoard(player, row, column);
        one.Move();
        one.printBoard();
        int counter = 1;

        while(counter <= 9){

            System.out.println("What player are you(X or O)?");
            player = in.next();
            System.out.println("What row do you want to play in(top, middle, bottom)?");
            row = in.next();
            System.out.println("What column do you want to play in(left, center, right)?");
            column = in.next();

            System.out.println(player + ", " + row + ", " + column);

            one.Move();
            counter ++;
            one.printBoard();

        }
    }
}

这是班级：

class TicTacToeBoard {

    private int[][]board = {
        {0,0,0},
        {0,0,0},
        {0,0,0} };

    String row, column, player;

    //Constructor
    public TicTacToeBoard(String r, String c, String p){
        row = r;
        column = c;
        player = p;
        }


    public void Move(){
        if (row == "top" && column == "left" && player == "X"){
            board[0][0] = 1;
        }
        if (row == "top" && column == "center" && player == "X"){
            board[0][1] = 1;
        }
        if (row == "top" && column == "right" && player == "X"){
            board[0][2] = 1;
        } 


        if (row == "middle" && column == "left" && player == "X"){
            board[1][0] = 1;
        }
        if (row == "middle" && column == "center" && player == "X"){
            board[1][1] = 1;
        }
        if (row == "middle" && column == "right" && player == "X"){
            board[1][2] = 1;
        } 


        if (row == "bottom" && column == "left" && player == "X"){
            board[2][0] = 1;
        }
        if (row == "bottom" && column == "center" && player == "X"){
            board[2][1] = 1;
        }
        if (row == "bottom" && column == "right" && player == "X"){
            board[2][2] = 1;
        } 





        if (row == "top" && column == "left" && player == "Y"){
            board[0][0] = 1;
        }
        if (row == "top" && column == "center" && player == "Y"){
            board[0][1] = 1;
        }
        if (row == "top" && column == "right" && player == "Y"){
            board[0][2] = 1;
        } 


        if (row == "middle" && column == "left" && player == "Y"){
            board[1][0] = 1;
        }
        if (row == "middle" && column == "center" && player == "Y"){
            board[1][1] = 1;
        }
        if (row == "middle" && column == "right" && player == "Y"){
            board[1][2] = 1;
        } 


        if (row == "bottom" && column == "left" && player == "Y"){
            board[2][0] = 1;
        }
        if (row == "bottom" && column == "center" && player == "Y"){
            board[2][1] = 1;
        }
        if (row == "bottom" && column == "right" && player == "Y"){
            board[2][2] = 1;
        }
    }

    public void printBoard(){
        for(int i = 0;i <= 2;i++){
            for(int j = 0; j <= 2;j++){
                System.out.print(board[i][j]);
            }
            System.out.println();
        }

    }
}

输出结果为：

你是哪个球员（X或O）？

X

你想在哪一排（顶部，中部，底部）？

顶

您想要播放哪一列（左，中，右）？

左

X，顶部，左侧

000 000 000

你是哪个球员（X或O）？

出于某种原因，无论我输入什么，董事会最终会全部为零。关于我做错了什么的想法？

Answer 1

我认为首先您需要使用row == "top"方法替换String.equals(String)和其他字符串比较

Answer 2

代码中的第一个问题是在TicTacToeBoard

的构造函数中

TicTacToeBoard（String r，String c，String p）期望行，列和播放器的contstructor参数但是你正在传递

TicTacToeBoard one = new TicTacToeBoard(player, row, column);

播放器，行和列哪个错了。

第二件事是你没有在你的while循环中更新TicTacToeBoard类的播放器，行，列值。每次当你在while循环中从用户那里获取输入时，你必须在TicTacToeBoard类中设置这些值。

Answer 3

首先，它们在Java中被称为方法，而不是函数。

并将row == "...."更改为row.equals(...)，因为这是我们比较java中字符串的方式。

应该这样做。

Answer 4

替换

之类的行

 if (row == "top" && column == "left" && player == "X"){
            board[0][0] = 1;
        }

与

if ("top".equalsIgnoreCase(row) && "left".equalsIgnoreCase(column) && "X".equalsIgnoreCase(player)){
            board[0][0] = 1;
        }

==运算符询问这两个项是否是同一个对象..不论它们是否具有相同的值。

类方法不起作用

4 个答案: