欢迎。有人能解释一下这段代码会发生什么吗？我想知道这是如何工作的（它来自http://rosettacode.org/wiki/Maze_generation#Python）。
from random import shuffle, randrange
def make_maze(w = 16, h = 8):
vis = [[0] * w + [1] for _ in range(h)] + [[1] * (w + 1)]
ver = [["| "] * w + ['|'] for _ in range(h)] + [[]]
hor = [["+--"] * w + ['+'] for _ in range(h + 1)]
def walk(x, y):
vis[y][x] = 1
d = [(x - 1, y), (x, y + 1), (x + 1, y), (x, y - 1)]
shuffle(d)
for (xx, yy) in d:
if vis[yy][xx]: continue
if xx == x: hor[max(y, yy)][x] = "+ "
if yy == y: ver[y][max(x, xx)] = " "
walk(xx, yy)
walk(randrange(w), randrange(h))
for (a, b) in zip(hor, ver):
print(''.join(a + ['\n'] + b))
make_maze()
答案 0 :(得分：8)
我对迷宫生成一无所知，但我也很好奇这段代码是如何工作的。以下是一些见解：
这两行打印迷宫：
for (a, b) in zip(hor, ver):
print(''.join(a + ['\n'] + b))
那么如果我们将这些行放在定义vis，ver和hor的三行之后会发生什么？我们得到了这个：
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
您甚至可以在递归调用walk(xx,yy)之前放置这两行，并查看迷宫演变的一些步骤：
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
| | | | | | | | | | | | | | | | |
+--+--+--+--+ +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+ +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+ +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+ +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+ +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+ + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+ + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+ + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ + + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ + + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ +--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ + + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ + + +--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ +--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+ +--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
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+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+
[...]
现在让我们关注walk(x,y)。正如它的名字和印刷输出所示，这个功能在迷宫中走动，以随机的方式移除墙壁，以便建立一条路径。
这个电话：
walk(randrange(w), randrange(h))
在迷宫内的随机位置初始化步行。网格中的每个单元格只访问一次;访问过的单元格标记在vis。
此行初始化一个包含当前单元格的所有四个邻居的数组：
d = [(x - 1, y), (x, y + 1), (x + 1, y), (x, y - 1)]
这些是以随机顺序访问的（感谢shuffle(d)）
这两条线是在建造迷宫路径时移除墙壁的那条线：
# remove horizontal wall, "+--" turns into "+ "
if xx == x: hor[max(y, yy)][x] = "+ "
# remove vertical wall, "|" turns into " "
if yy == y: ver[y][max(x, xx)] = " "
关于这个算法还有更多要说的内容（参见Jongware的评论），但就理解这段特殊代码而言，这些是你可以做的事情。