Question

我试图弄清楚如何运行我的数据库，收集相似的节点，然后将它们合并到一个节点中，并将先前的关系重定向到新创建的节点。我基本上创建了一堆节点，其中部分或全部属性都有信息，如下所示：

MERGE (company:Company{Name: 'Ford'})
MERGE (person:Person{Name: 'me'})
MERGE (car:Car{Make:'Ford', Model:'Aerostar', Color:'Blue', Transmission:'Auto'})

但我意外地复制了本应合并的节点，而是创建了新节点：

MERGE (car:Car{Make:'Ford', Model:'Aerostar', Color:'', Transmission:''})
MERGE (car:Car{Make:'Ford', Model:'Aerostar', Color:'Blue', Transmission:''})
MERGE (car:Car{Make:'Ford', Model:'Aerostar', Color:'Blue', Transmission:'Auto'})
MERGE (person)-[:drives]->(car)-[:parent_company]->(company)

所以，我想要做的是拿出我意外创建的三个(car)个节点，合并它们的所有属性，删除额外节点创建的额外关系并更正路径，所以(me)会只有一个[:drives]关系连接到由(car)个关系连接的单个[:parent_company]。

这是我尝试过的，但无法弄清楚：

MATCH p=(car:Car{Make:'Ford', Model:'Aerostar'})<-[:drives]-(person:Person{Name:'me'})
FOREACH (car in nodes (p) | SET Car.Color: 'Blue', Car.Transmission:'Auto')
/////This is where I'm stuck

编辑：另一次尝试（我得到＆＃34; r已经宣布错误）：

START n = node(3) //node id for complete 'aerostar' node
WITH n
MATCH (company)<-[:parent_company]-(car:Car{Make:'Ford', Model:'Aerostar')<-[r:drives]-(person)
WITH n, company, r, car, person
MERGE (person)-[r]->(n)-[:parent_company]->(company)
DELETE car

Answer 1

[EDITED]

这对你有用吗？

MATCH (car:Car{Make:'Ford', Model:'Aerostar'})<-[d:drives]-(person:Person{Name:'me'})
DELETE d, car
WITH person
CREATE (car:Car{Make:'Ford', Model:'Aerostar', Color:'Blue', Transmission:'Auto'})<-[d:drives]-(person);

Answer 2

我终于想出了如何做到这一点：

MATCH (car:Car{Make:'Ford', Model:'Aerostar'})<-[d:drives]-(person:Person{Name:'me'})
WITH car,d
SKIP 1
DELETE car,d

在密码中进行foreach查询以合并类似的节点

2 个答案: