Question

我有一个php语句，它使用各种sql查询将数据输入到两个不同的表中。第一个查询工作正常，但一旦我越过

if (isset($origin, $destination));

指出，虽然脚本在底部重定向，但它没有任何作用，就好像它完成一样。

对于出现问题的任何帮助都将不胜感激。

$sql="INSERT INTO journey_boards (headline, text, tag, origin, destination, userid)
VALUES
('$_POST[posttitle]', '$_POST[posttext]', '$_POST[tag]', '$_POST[origin]',    '$_POST[destination]', '$_SESSION[id]')";

$origin = $_POST[origin];
$destination = $_POST[destination];

if (isset($origin, $destination)) {
$query = mysqli_query($con, "SELECT * FROM journey_ranking WHERE origin = $origin AND     destination = $destination");
}
$count = mysql_num_rows($query);

if ($count = 1) {
    $sql2 = "UPDATE journey_ranking SET rank = rank + 1 WHERE origin = $origin AND destination = $destination";
} else {
    $sql3 = "INSERT INTO journey_ranking (origin, destination, rank)
    VALUES
    ('$_POST[origin]', '$_POST[destination]', 1)";
    }
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}



header('location: journeys.php');

mysqli_close($con);

Answer 1

另外，改变

if (isset($origin, $destination)) {
$query = mysqli_query($con, "SELECT * FROM journey_ranking WHERE origin = $origin AND     destination = $destination");
}
$count = mysql_num_rows($query);

到

if (isset($origin, $destination)) {
$query = mysqli_query($con, "SELECT * FROM journey_ranking WHERE origin = $origin AND     destination = $destination");
$count = mysql_num_rows($query);
} else $count = 0;

和

if ($count = 1) {

应该是

if ($count == 1) {

多个SQL查询无法正常工作

1 个答案: