Question

我创建了一个html页面。这是以下代码：

           <title>Post AD</title>
    </head>
  <body>

      <form method="POST" action="postad.php">

     <table>
    <tr>
    <td>AdName:</td>
    <td><input type="text" name="adname"></td>
     </tr>
     <tr>
    <td>AdCategory</td>
         <td>
            <select name="categories">
             <?php include 'getcategories.php'; 
             echo '<option value="'.$categoryname.'">'.$categoryname.'</option>';
             ?>
</select>";




  </td>
     </tr>
     <tr>
    <td>Contact Number</td>
    <td><input type="text" name="contactnumber"></td>
     </tr>
     <tr>
    <td>Image</td>
    <td><input type="text" name="image"></td>
     </tr>
     <tr>
    <td>Description</td>
    <td><input type="text" name="description"></td>
     </tr>
        <tr>
    <td>Expiration Date</td>
    <td><input type="text" name="expirationdate"></td>
     </tr>
     <tr>
     <td id="btn"><input type="submit" value='submit' name="submit"></td>
    </tr>    
    </table>


    </form>
      </body>
</html>

我还有另一个php页面getcategories.php

<?php include 'connect.php'; 

            $sql = "SELECT CatName FROM categories order by CatName";
            $result = $db->query($sql);
           // $options="";
//echo "<select value='categories'>";       
while($row = $result->fetch_array()) {

        $categoryname=$row['CatName']; 
        //echo "$categoryname\n";
       //$options= '<option value="'.$categoryname.'">'.$categoryname.'</option>'; 
       // echo "$options\n";
    // echo '<option value="'.$categoryname.'">'.$categoryname.'</option>';

}
// echo "</select>";
?>

getcategories.php页面的主要目标是从数据库中提取数据，页面postad.html页面是将getctegories.php的数据显示在postad.html的下拉列表中。有没有办法不使用java脚本只用php和mysql来做这个吗？请帮助。谢谢。

从PHP页面中的mysql中提取数据，并在html页面的下拉列表中显示

0 个答案: