我是php＆amp; amp;的新手MySQL的 基本上我想要做的是能够从表中检索数据 在MySQL数据库中，并将其放在下拉菜单中。 在我填写其他字段后，我想从下拉菜单中将数据写入同一数据库中的另一个表。
这是我的insert.php文件
<?php
#### INSERTS A SINGLE CUSTOMER IN Company-->Customer Database with UTF8 Change for special German Characters - Cyrilic Doesnt work - Other change then utf8 ???
#### Getting Data from Index.php
$servername = "127.0.0.1";
$username = "root";
$password = "";
$dbname = "company";
//making an array with the data recieved, to use as named placeholders for INSERT by PDO.
#### Getting DAta from Index.php
$data = array('CustomerName' => $_POST['CustomerName'] , 'Address1' => $_POST['Address1'], 'Address2' => $_POST['Address2'], 'City' => $_POST['City'], 'PostCode' => $_POST['PostCode'], 'CountryID' => $_POST['CountryID'], 'ContactName' => $_POST['ContactName'], 'ContactEmail' => $_POST['ContactEmail'], 'ContactPhone' => $_POST['ContactPhone'], 'ContactFax' => $_POST['ContactFax'], 'Website' => $_POST['Website']);
try {
// preparing database handle $dbh
$dbh = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password,array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8")); ### Database Connect with Special characters Change
// set the PDO error mode to exception
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// query with named placeholders to avoid sql injections
$query = "INSERT INTO customer (CustomerName, Address1, Address2, City, PostCode, CountryID, ContactName, ContactEmail, ContactPhone, ContactFax, Website )
VALUES (:CustomerName, :Address1, :Address2, :City, :PostCode, :CountryID, :ContactName, :ContactEmail, :ContactPhone, :ContactFax, :Website )";
//statement handle $sth
$sth = $dbh->prepare($query);
$sth->execute($data);
echo "New record created successfully";
}
catch(PDOException $e)
{
echo $sql . "<br>" . $e->getMessage();
}
$dbh = null;
?>
这是来自html页面的来源
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add New Product</title>
</head>
<body>
<form action="insert.php" method="post">
<p>
<label for="CustomerName">CustomerName:</label>
<input type="text" name="CustomerName" id="CustomerName">
</p>
<p>
<label for="Address1">Address 1:</label>
<input type="text" name="Address1" id="Address1">
</p>
<p>
<label for="Address2">Address 2:</label>
<input type="text" name="Address2" id="Address2">
</p>
<p>
<label for="City">City:</label>
<input type="text" name="City" id="City">
</p>
<p>
<label for="PostCode">Post Code:</label>
<input type="text" name="PostCode" id="PostCode">
</p>
<p>
<label for="CountryID">Country ID:</label>
<input type="text" name="CountryID" id="CountryID">
</p>
<p>
<label for="ContactName">Contact Name:</label>
<input type="text" name="ContactName" id="ContactName">
</p>
<p>
<label for="ContactEmail">Contact Email:</label>
<input type="text" name="ContactEmail" id="ContactEmail">
</p>
<p>
<label for="ContactPhone">Contact Phone:</label>
<input type="text" name="ContactPhone" id="ContactPhone">
</p>
<p>
<label for="ContactFax">Contact Fax:</label>
<input type="text" name="ContactFax" id="ContactFax">
</p>
<p>
<label for="Website">Website:</label>
<input type="text" name="Website" id="Website">
</p>
<input type="submit" value="Add Records">
</form>
</body>
</html>
所以我想添加这个PHP代码，它会拉出国家/地区列表和电话号码的前缀，然后当我点击提交按钮时，下拉菜单的实际输出将写入客户表中
<p>
<label for="CountryID">Country:</label>
<?php
$servername = "localhost";
$username = "root";
$password ="";
$dbname = "company";
$con_qnt = mysqli_connect($servername, $username, $password, $dbname);
if(!mysqli_connect("localhost","root",""))
{
die('oops connection problem ! --> '.mysqli_connect_error());
}
if(!mysqli_select_db($con_qnt, "company"))
{
die('oops database selection problem ! --> '.mysqli_connect_error());
}
$sql = "SELECT * FROM country";
$result = mysqli_query($con_qnt, "SELECT * FROM country" );
echo "<select name='label'>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['CountryName' ] . "'>" . $row['CountryName' ] . " (" .$row['PhonePrefix' ] . ")" . "</option>";
}
echo "</select>";
?>
<name="CountryID" id="CountryID">
</p>
我甚至不知道这是否可行 - 我搜索了很长时间但找不到任何我需要的东西。大多数情况下，我发现了硬编码的html下拉菜单。事实上，硬编码将适用于各国，但如果我希望它能够在下拉菜单中显示让我们说产品，它就无法工作。谢谢大家 。
答案 0 :(得分：0)
您好我刚刚做了一个快速示例，回答了有关如何使用数据库中的数据填充下拉列表的问题。 在这个例子中，我使用了
JQuery的AJAX功能
首先，对于后端，（这只是选择数据的快速示例。请勿将此作为未来代码的模式使用
if(choice.get() == 1) {......}
我再说一遍。这只是为了快速参考。不要将它用作代码的模式。
因此，使用该代码，我们现在已从表国家/地区选择数据，并使用<?php
$dbh = new PDO("mysql:host=localhost;dbname=dbhelp", 'root', 'pup');
$stmt = $dbh->prepare("SELECT * from t_country");
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($result);
?>
以json格式制作数据。在这里阅读更多相关信息。 http://php.net/manual/en/function.json-encode.php
下一个是前端（HTML部分）
json_encode答案 1 :(得分：0)
如果我找对你，你想要替换它：
<p>
<label for="CountryID">Country ID:</label>
<input type="text" name="CountryID" id="CountryID">
</p>
通过下拉菜单，您可以从下拉列表中快速选择国家/地区，而不是记住每个国家/地区的ID。要创建select，您正在使用此代码：
<p>
<label for="CountryID">Country:</label>
<?php
// some code here that I removed to avoid noise
$sql = "SELECT * FROM country";
$result = mysqli_query($con_qnt, "SELECT * FROM country" );
echo "<select name='label'>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['CountryName' ] . "'>" . $row['CountryName' ] . " (" .$row['PhonePrefix' ] . ")" . "</option>";
}
echo "</select>";
?>
<name="CountryID" id="CountryID">
</p>
在解决一些问题后，这应该可以正常工作：
如果您要将input替换为select，select应与input同名，以便自动处理该值。现在select有“标签”作为名称，并且有一个奇怪的（和不正确的）name标签。解决这个问题：
摆脱不必要的name标记。
将name中的select属性替换为值“CountryID”：
echo "<select name='CountryID'>";
option值应为国家/地区ID，因此，除非ID是国家/地区名称（不是最佳选择），否则您使用的值不正确。也改变那条线：
echo "<option value='" . $row['CountryID' ] . "'>" . $row['CountryName' ] . " (" .$row['PhonePrefix' ] . ")" . "</option>";
（将CountryID视为ID，将其替换为正确的列名称。）
我认为通过这两个更改，其余的代码应该可以正常使用insert.php，根本不需要任何更新。最后它看起来像这样：
<p>
<label for="CountryID">Country:</label>
<?php
// some code here that I removed to avoid noise
$sql = "SELECT * FROM country";
$result = mysqli_query($con_qnt, "SELECT * FROM country" );
echo "<select name='CountryID'>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['CountryID' ] . "'>" . $row['CountryName' ] . " (" .$row['PhonePrefix' ] . ")" . "</option>";
}
echo "</select>";
?>
</p>