Question

我想使用pivot查询的stuff部分按asc顺序对日期进行排序。

示例：

DECLARE @cols AS NVARCHAR(MAX),
        @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT  distinct ',' + QUOTENAME(column_date)--(column_date)
              FROM #temp 
              order by column_date /* Error occured here*/
        FOR XML PATH(''), TYPE
        ).value('.', 'NVARCHAR(MAX)') 
    ,1,1,'')
PRINT(@cols)

通过order by子句获取上述脚本附近的错误。

错误详情：

Msg 145, Level 15, State 1, Line 4  
ORDER BY items must appear in the select list if SELECT DISTINCT is specified.

Answer 1

试试这个：

您可以按column_date使用分组，它将返回不同的日期

DECLARE @cols AS NVARCHAR(MAX),
        @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT    ',' + QUOTENAME(column_date)--(column_date)
              FROM #temp 
              GROUP BY column_date
              order by column_date /* Error occured here*/
        FOR XML PATH(''), TYPE
        ).value('.', 'NVARCHAR(MAX)') 
    ,1,1,'')
PRINT(@cols)

Answer 2

我不知道你为什么在没有order by的情况下使用Top clause。试试这个..

SELECT @cols = ',' + column_date
FROM   (SELECT DISTINCT Quotename(column_date) column_date
        FROM   #temp) A
ORDER  BY column_date

SELECT @cols = RIGHT(@cols, Len(@cols) - 1)

在枢轴查询的东西部分中排序

2 个答案: