Question

这里的新蟒蛇人

所以我正在尝试制作一个基本的轮盘游戏，有5种选择供玩家选择。我设法让脚本运行没有错误，但是＆＃34; win_loss＆＃34;似乎没有注册，或者至少不是if / elif部分。我只能假设我没有在顶部正确识别某些东西。

我很乐意接受一个完整的答案，指导可能会帮助我更多地倾斜。无论哪种方式，欢迎所有帮助。

import random

red = (1,3,5,7,9,12,14,16,18,21,23,25,27,30,32,34,36)
black = (2,4,6,8,10,11,13,15,17,19,20,22,24,26,28,29,31,33,35)
green = 0
even = (2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36)
odd = (1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35)

def main():
    print('Red = 1')
    print('Black = 2')
    print('Green = 3')
    print('Odd = 4')
    print('Even = 5')
    print('-=-=-=-=-=-=-=-=-=-=-')
    player = int(input('Place your bet, 1-5: '))
    print('-=-=-=-=-=-=-=-=-=-=-')

    roll()
    win_loss()

def roll():
    spin = random.randint(1,36)
    print('Landed on: ',spin)
    print('-=-=-=-=-=-=-=-=-=-=-')

def win_loss():
    if (roll) == red:
        print('You won $.45')
    elif (roll) == black:
        print('You won $.45')
    elif (roll) == green:
        print('You won $5.00')
    elif (roll) == even:
        print('You won $.45')
    elif (roll) == odd:
        print('You won $.45')
    else:
        print('You lost')

main()

Answer 1

您的功能不会返回任何内容而且他们不接受参数。要让你的win_loss()函数知道滚动结果是什么，你需要做这样的事情：

def roll():
    return random.randint(0,36)  # Pointed out by Lallen, you need to include 0
    # move the print statements outside the function

def win_loss(roll):  # note the parameter here
    if (roll) == red:
        print('You won $.45')
    elif (roll) == black:
        print('You won $.45')
    elif (roll) == green:
        print('You won $5.00')
    elif (roll) == even:
        print('You won $.45')
    elif (roll) == odd:
        print('You won $.45')
    else:
        print('You lost')

在你的剧本中：

result = roll()
win_loss(result)

在此处详细了解functions and parameters。

enter code here

另请注意，您的布尔运算不起作用。您需要测试滚动的结果是否in您的元组不等于它们。像这样：

# Note the curly braces. As Marius suggested using sets here will make your program a little more efficient
red = {1,3,5,7,9,12,14,16,18,21,23,25,27,30,32,34,36}
black = {2,4,6,8,10,11,13,15,17,19,20,22,24,26,28,29,31,33,35}
green = 0
even = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36}
odd = {1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35}

...

def win_loss(roll):  # note the parameter here
    if roll in red:  
        print('You won $.45')

现在效果会更好，因为1 in red为True而1 == red为False。

您还需要确保玩家下注是赢/输：

def win_loss(roll, player):  # note the new player parameter here
        if roll in red and player == 1:  # note the comparison between the players input and the choices you laid out in the beginning.
            print('You won $.45')

额外的布尔表达式将确保滚动位于red并且玩家下注为红色。必须对所有不同的检查进行此操作。

这些以及评论中列出的要点是一些可以帮助您的事情。我强烈建议你做一些阅读或者一些在线教程，因为你的代码中存在很多潜在的问题。

python中的基本5选择轮盘赌游戏

1 个答案: