Python中的基本轮盘模拟器(仅限红色/黑色)

时间:2013-09-03 09:35:44

标签: python python-2.7

我在python中编写了一个非常基本的轮盘模拟器。目前,我只专注于红/黑投注(基本上与投注头或尾,使用硬币相同)。

我的代码有各种各样的问题。请原谅我对该语言的基本知识。

import random

# Defines initial amounts of money and losses
money = 50
losses = 0


# Asks user how much to bet
def roulette_sim():
    print "How much do you want to bet?"
    bet = raw_input("> ")
    if bet > money:
        bet_too_much()
    else:
        red_or_black()


# Prevents one from betting more money than one has
def bet_too_much():
    print "You do not have all that money. Please bet again." 
    raw_input("Press ENTER to continue> ")
    roulette_sim()

# Asks user to select red or black, starts the sim, modifies money/losses
def red_or_black():
    print "OK, you bet %r" %  (bet)
    print "Red or black?"
    answer = raw_input("> ")
    number = random.randint(1, 2)
    if number == 1 and answer == "red":
        print "You win!"
        money += bet
        print "You now have %r money" % (money)
        print "Your losses are %r" % (losses)
        replay()
    elif number == 2 and answer == "black":
        print "You win!"
        money += bet
        print "You now have %r money" % (money)
        print "Your losses are %r" % (losses)
        replay()
    else:
        print "You lost!"
        money -= bet
        losses += bet
        print "You now have %r money" % (money)
        print "Your losses are %r" % (losses)
        replay()

# Asks user whether he/she wants to play again
def replay():
    print "Do you want to play again?"
    play_again = raw_input("y/n> ")
    if play_again == "y":
        roulette_sim()
    else:
        print "OK, bye loser!"


roulette_sim()

到目前为止的第一个问题:bet_too_much功能不起作用。无论我输入什么金额,该计划都说它太多了(即:“赌注总是大于金钱'”)。为什么呢?

到目前为止的第二个问题:当我想添加/减去' bet'来自' money'通过使用,例如:     钱+ =下注 python将此视为用字符串对int求结(至少我认为是这样)而不是求和两个变量。这是为什么?

任何帮助都将不胜感激。

由于

3 个答案:

答案 0 :(得分:2)

这两件事都发生了,因为Python不进行隐式转换。你必须明确告诉它你想要一个整数,它不会为你做。 所以,对于第一个问题:

bet = raw_input("> ") 
if bet > money:
...

必须是

bet = raw_input("> ")
bet = int(bet)
if bet > money:
...

因为您不想将字符串与整数进行比较(您可以,但结果是您现在得到的结果)。

对于第二个,你也必须明确:

money += int(bet)

(当然,如果你已经将bet转换成了一个int,那你很好。)

Javascript因执行此隐式转换而臭名昭着,因此如果您恰好熟悉该类型或类似的语言,请忘记并明确您正在使用的类型。总的来说,这更安全。

答案 1 :(得分:0)

raw_input()函数返回字符串值,但money是整数。将字符串与数字进行比较总是会使Python 2的排序数字小于字符串。

raw_input()的结果转换为整数:

def roulette_sim():
    print "How much do you want to bet?"
    bet = int(raw_input("> "))

如果给定的输入不是有效数字,则可能抛出ValueError异常;您可能希望捕获该异常并告诉用户输入一个数字:

def roulette_sim():
    print "How much do you want to bet?"
    while True:
        try:
            bet = int(raw_input("> "))
        except ValueError:
            print "Please enter a valid amount, a number."
        else:
            break

答案 2 :(得分:0)

您正在将从raw_input(“>”)获得的字符串与整数进行比较。这不会很好。 请尝试使用此功能(尚未完全测试):

def roulette_sim():
    while(1):
        print "How much do you want to bet?"
        try:
           bet = int(raw_input("> "))
           break
        except ValueError:
           print 'You need to input a number'

    if bet > money:
        bet_too_much()
    else:
        red_or_black()

编辑:根据评论更改为“除ValueError”。我知道我对python编程的处理部分有点懒惰,但也许我不应该教给别人: - )