Question

如果我有

l = ['a','b','x','f']

我想将'x'替换为sub_list = ['c','d','e']

最好的方法是什么？我有，

l = l[:index_x] + sub_list + l[index_x+1:]

Answer 1

l = ['a','b','x','f']

sub_list = ['c','d','e']

ind = l.index("x")
l[ind:ind+1] = sub_list

print(l)
['a', 'b', 'c', 'd', 'e', 'f']

如果您有一个包含多个x's使用索引的列表，则会替换第一个x。

如果您想要替换所有x's：

l = ['a','b','x','f',"x"]
sub_list = ['c','d','e']
for ind, ele in enumerate(l): # use l[:] if the element to be replaced is in sub_list
    if ele == "x":
        l[ind:ind+1] = sub_list
print(l)
['a', 'b', 'c', 'd', 'e', 'f', 'c', 'd', 'e']

Answer 2

您可以找到要替换的元素的索引，然后将子列表分配给原始列表的切片。

def replaceWithSublist(l, sub, elem):
    index = l.index(elem)
    l[index : index+1] = sub
    return l

>>> l = ['a','b','x','f']
>>> sublist = ['c','d','e']

>>> replaceWithSublist(l, sublist, 'x')
['a', 'b', 'c', 'd', 'e', 'f']

Answer 3

另一种方法是使用insert()方法

l        = ['a','b','x','f']
sub_list = ['c','d','e']
ind      = l.index('x')

l.pop(ind)
for item in reversed(sub_list):
    l.insert(ind, item)

用多个值替换列表的元素

3 个答案: