Question

因此，我正在尝试创建一个网格，可以将其单独的“网格方块”替换为任何给定的符号。网格工作正常，但它由列表中的列表组成。

这是代码

size = 49
feild = []
for i in range(size):
    feild.append([])
for i in range(size):
    feild[i].append("#")
feild[4][4] = "@" #This is one of the methods of replacing that I have tried
for i in range(size):
    p_feild = str(feild)
    p_feild2 = p_feild.replace("[", "")
    p_feild3 = p_feild2.replace("]", "")
    p_feild4 = p_feild3.replace(",", "")
    p_feild5 = p_feild4.replace("'", "")
    print(p_feild5)

正如您所看到的，这是我尝试替换元素的一种方式，我也尝试过：

feild[4[4]] = "@"

和

feild[4] = "@"

第一个用“@”替换左边的所有“＃”4个元素第二个给出以下错误

TypeError: 'int' object is not subscriptable

Answer 1

制作#网格，第3行第3列替换为@：

>>> size = 5
>>> c = '#'
>>> g = [size*[c] for i in range(size)]
>>> g[3][3] = '@'
>>> print('\n'.join(' '.join(row) for row in g))
# # # # #
# # # # #
# # # # #
# # # @ #
# # # # #

Answer 2

可能你正在寻找： -

size = 49
feild = []
for i in range(size):
    feild.append([])
for i in range(size):
    map(feild[i].append, ["#" for _ in xrange(size)])
i = 4
feild[i][0] = "@"

用字符串替换list元素中的list元素

2 个答案: