Question

截至目前，我可以在数据库中上传我的图像，当我旋转图像时出现问题。上传的图像不是旋转的图像，它仍然是我上传的图像，我没有旋转。

如何上传旋转的图像？

Stream FileStream = File.OpenRead(ServerPath + Filename);
       // Stream FileStream = FileUpload1.PostedFile.InputStream;
       // System.Drawing.Image.FromFile(ServerPath + Filename);
        //System.Drawing.Bitmap postedimage = new System.Drawing.Bitmap(FileStream);

        objImage = ScaleImage(PostedImage, 73);
        if (FileType != "jpg" && FileType != "JPG")
        {
            objImage.Save(ServerPath + jpgFileName, ImageFormat.Jpeg);
        }
        else
        {
            //objImage.Save(ServerPath + Filename);
        }

        img = new byte[FileStream.Length];
        contentlength = FileStream.Length;

        if (contentlength > 506000)
        {
            ClientScript.RegisterClientScriptBlock(typeof(Page), "ClosePopup", "File is to large! Maximum size is 8kb", true);
        }

        else if (contentlength <= 506000)
        {
            //ImageConverter converter = new ImageConverter();
            //byte[] bytestr = (byte[])converter.ConvertTo(objImage, typeof(byte[]));
            //fs.InputStream.Read(img, 0, fs.ContentLength);
            byte[] bytestr = null;
            var fsm = ToStream(objImage, ImageFormat.Jpeg);
            //Stream fsm = ScaleImage(objImage, 73);
            BinaryReader br = new BinaryReader(fsm);
            bytestr = br.ReadBytes((int)fsm.Length);

            SqlCommand cmd = new SqlCommand("Select * FROM tblphotoupload where mem_cardno = '" + sParameter + "'", connection);

            SqlDataReader alinan_veri3;
            alinan_veri3 = cmd.ExecuteReader();

            if (alinan_veri3.Read())
            {
                int sct = 2;
                int a = Convert.ToInt32(alinan_veri3["upload_count"]);

                if (sct == 2)
                {
                    if (a >= 2) a = 2;
                    sql = "update tblphotoupload set mem_photo" + Convert.ToString(a + 1) + " = @img, upload_date" + Convert.ToString(a + 1) + " = '" + sDateTime + "', mem_contenttype" + Convert.ToString(a + 1) + " = '" + FileType + "', mem_photofile" + Convert.ToString(a + 1) + " = '" + Filename + "', upload_count='" + (a + 1) + "' where mem_cardno = '" + sParameter + "'";
                    connection.Close();
                    SqlConnection connection2 = new SqlConnection(ConfigurationManager.ConnectionStrings["EKConn"].ConnectionString);
                    connection2.Open();

                    SqlCommand cmd2 = new SqlCommand(sql, connection2);
                    cmd2.Parameters.Add(new SqlParameter("@img", bytestr));
                    cmd2.ExecuteNonQuery();
                    connection2.Close();
                }

            }
            else
            {
                //string ole;
                sql = "insert into tblphotoupload (mem_cardno, mem_photo1, upload_date1, upload_count, mem_contenttype1, mem_photofile1) values ('" + sParameter + "', @img, '" + sDateTime + "','1','" + FileType + "','" + Filename + "')";
                connection.Close();
                SqlConnection connection2 = new SqlConnection(ConfigurationManager.ConnectionStrings["EKConn"].ConnectionString);
                connection2.Open();
                SqlCommand cmd2 = new SqlCommand(sql, connection2);
                cmd2.Parameters.Add(new SqlParameter("@img", bytestr));
                cmd2.ExecuteNonQuery();
                connection2.Close();
            }
        }
    }

Answer 1

首先确保您的文件保存在磁盘上，然后将文件保存到DB中。

如果这无济于事，您可能需要：

正确旋转，旋转可能仅由图像查看器保存而不更改磁盘上的图像，我遇到了Picassa的问题
在代码中旋转它（旋转字节）

如何在文件中获取旋转的图像

1 个答案: