使用Python中的networkX包绘制图分区

Question

我有一个图表对象G，其中包含0到n-1的节点和两个列表L1 L2，它们是{G节点的分区1}}。我想以这样的方式绘制G：节点结果分为两个块：一个相对于L1，另一个相对于L2。图片的目的应该是证明L1和L2之间的联系。你能帮我做一下这个任务吗？

非常感谢提前。

Answer 1

分别绘制每个图形并使用不相交的乘积生成一个显示边缘的新图形：

import networkx as nx

n1, n2 = 10, 10

# Define two random graphs
g1 = nx.gnm_random_graph(n1,20)
g2 = nx.gnm_random_graph(n2,20)
pos1 = nx.graphviz_layout(g1,prog='dot')
pos2 = nx.graphviz_layout(g2,prog='dot')

# Shift graph2
shift = 400
for key in pos2:
    pos2[key] = (pos2[key][0]+shift, pos2[key][1])

# Combine the graphs and remove all edges
g12 = nx.disjoint_union(g1,g2)
for i,j in g12.edges():
    g12.remove_edge(i,j)

# Add the conjoined edges
g12.add_edge(5, 7+n1)
g12.add_edge(2, 3+n1)
g12.add_edge(8, 7+n1)

# Set the new pos for g12
pos12 = pos1.copy()
for node in pos2:
    pos12[node+n2] = pos2[node]

# Show the results, make the conjoined edges darker

import pylab as plt
nx.draw_networkx(g1,pos=pos1,alpha=0.5)
nx.draw_networkx(g2,pos=pos2,alpha=0.5)
nx.draw_networkx_edges(g12,pos=pos12,width=5)
plt.axis('off')
plt.show()