Question

这是我的代码，它正在工作，但它只打印最小值并将其打印为负数。这段代码出了什么问题？

#include <stdio.h>

int main(void) {

    double x[5][5],Max, Min;
    int i, j;

    for (i = 0; i<5; i++)
    {
        for (j = 0; j<5; j++)
            scanf("%lf", &x[i][j]);
    }
    Max = x[0][0];
    Min = x[0][0];

        if (x[i][j] > x[0][0])
            printf("Max= %f\n", x[i][j]);

    else if (x[i][j] < x[0][0])
        printf("Min = %f\n", x[i][j]);

    return 0;
}

Answer 1

接收输入后，您永远不会遍历数组，因为您位于for循环之外。你可以这样做：

Max = x[0][0];
Min = x[0][0];

for(i = 0; i < 5; ++i)
{
    for(j = 0; j < 5; ++j)
    {
        if (x[i][j] < Min)   // Is current element smaller than Min?
            Min = x[i][j];        // If so, update Min
        if (x[i][j] > Max)   // Is current element greater than Max?
            Max = x[i][j];        // If so, update Max
    }
}

printf("Max= %f\n", Max);
printf("Min= %f\n", Min);

Answer 2

你忘了在循环中附上最小值和最大值的搜索。：）

尝试以下

for (i = 0; i<5; i++)
{
    for (j = 0; j<5; j++)
        scanf("%lf", &x[i][j]);
}
Max = x[0][0];
Min = x[0][0];

for (i = 0; i<5; i++)
{
    for (j = 0; j<5; j++)
    {
        if ( Max < x[i][j] )
        {
            Max = x[i][j];
        }
        else if ( x[i][j] < Min )
        {
            Min = x[i][j];
        }
    }
}

printf( "Max = %f\n", Max );
printf( "Min = %f\n", Min );

Answer 3

您需要遍历2D数组中的所有值以检查2D数组的所有值，并相应地设置max和min变量：

    Max = x[0][0]; //set max as the first element
    Min = x[0][0];  //set min as the first element
    for (i = 0; i<5; i++) //loop through each row
    {
        for (j = 0; j<5; j++) //loop through each column
    {
            if (x[i][j] > Max) //if current value is more than max
            Max=x[i][j];
            if (x[i][j] < Min) //if current value is less than min
            Min=x[i][j];
        }
    }

    printf("Max= %f\n", Max);   
    printf("Min = %f\n", Min);

如何在2D数组中打印最大值和最小值？

3 个答案: