Question

以下是我遇到问题的一些代码的一部分：

def func():
    for i in range(len(titleList)):
        print titleList[i] + ' -- ' + artistList[i] + ' -- ' + albumList[i] + ' --',
        print yearList[i] + ' -- ' + commentList[i]

def sequentialSearch(albumList, item):
    pos = 0
    found = False
    while pos < len(albumList) and not found:
        if albumList[pos] == item:
            found = True
        else:
            pos = pos + 1
    return found

num = input("What would you like to do?\n1. Print all the contents of the database\n2. Find all the songs on a particular album\n3. Quit\nPlease Enter 1, 2, or 3: ")
if num == 3:
    print "Goodbye"
else:
    while num != 3:
        if num == 1:
            func()
        if num == 2:
            item = raw_input("Please enter the album: ")
            seqentialSearch(albumList, item)
        else:
            print "Invald Input"

我有一个数据库，该程序正在从中提取数据。我需要它表现得像这样：

如果输入1，程序将返回数据库的全部内容
如果输入2，我希望程序使用顺序搜索打印该相册中歌曲的所有信息
如果输入3，我只想打印＆＃34;再见＆＃34;

我遇到的两个问题是：

我的顺序搜索代码未返回正确的信息
我希望程序循环直到输入3。

如何解决这些问题？

Answer 1

您的sequentialSearch功能不打印任何内容。并且您不需要found变量，当您找到匹配项时，您可以从该函数return获得。{/ p>

def sequentialSearch(albumList, item):
    for i in range(len(albumlist))
        if albumList[i] == item:
            print titleList[i] + ' -- ' + artistList[i] + ' -- ' + albumList[i] + ' --',
            print yearList[i] + ' -- ' + commentList[i]
            return true
    return false

在您的主代码中，您的while循环永远不会结束，因为您在循环外请求num。使用：

while true:
    num = input("What would you like to do?\n1. Print all the contents of the database\n2. Find all the songs on a particular album\n3. Quit\nPlease Enter 1, 2, or 3: ")
    if num == 3:
        print "Goodbye"
        break
    elif num == 1:
        func()
    elif num == 2:
        item = raw_input("Please enter the album: ")
        sequentialSearch(albumList, item)
    else:
        print "Invald Input"

Answer 2

可以根据需要控制选项：

num = 0
while num !=3:
    num = input("What would you like to do?\n1. Print all the contents of the database\n2. Find all the songs on a particular album\n3. Quit\nPlease Enter 1, 2, or 3: ")
    if num == 1:
        func()
    elif num == 2:
        item = raw_input("Please enter the album: ")
        seqentialSearch(albumList, item)
    elif num != 3:
        print "Invald Input"
print "Goodbye"

顺序搜索数据库

2 个答案: