Question

我有一个附加到amount的{{1}}个（基于$$$销售额）的数组（其中一些id是基于谁做的id一笔销售）。我的目标是收集总共amount个，并将每个总数附加到出售的id中（从数组中截断相同的id）。我老实说不知道如何解决这个问题，因为我还在学习。

while ($row) {
    $operearnedArray[] = array(
      'amount' => $row['ChargeAmount'], 
      'id' => $row['OperatorID']);
}
//$operearnedArray returns the array with each "amount" attached to "id"
foreach ($operearnedArray as $key => $value) {
    if($value['id'] == '' || $value['id'] == null) {
        continue;
    }
    if(array_key_exists($value['id'], $operSums)) {
        $operSums[$value['id']] += $value['amount'];
    } else {
        //I'm not sure where to go from here...
    }
}

Answer 1

对于我来说，您的代码看起来很好，对于评论来说，这是一个简单的

$operSums[$value['id']] = $value['amount'];

应该做的伎俩。当然，建议检查现有密钥，但

foreach ($operearnedArray as $key => $value) {
    if($value['id'] == '' || $value['id'] == null) {
        continue;
    }
    $operSums[$value['id']] += $value['amount'];
}

应该也可以正常工作，正如您在this demo中看到的那样。

Answer 2

尝试：

while ($row) {
    $operearnedArray[] = array(
      'amount' => $row['ChargeAmount'], 
      'id' => $row['OperatorID']);
}

$operSums = array();
foreach ( $operearnedArray as $sale ) {
    if ( ! $sale['id'] ) {
        continue;
    }
    $operSums[$sale['id']] += $sale['amount'];
}
// do something with the result, let's just look at it:
var_dump( $operSums );

有效：http://codepad.org/xGMNQauW

使用array_key_exists将总金额与id配对

2 个答案: