Question

第一张表

属性

id   Name

 1   ABC
 2   XYZ
 3   GHQ

Property_options

 id   property_id  option

 1      1         terrace
 2      1         balcony
 3      1         garaj
 1      2         terrace
 2      2         balcony
 3      2         garaj

我想使用三个选项过滤属性（terrace，balcony和garaj）

如果用户检查三个选项，那么只有那些属性会有三个选项，而不是两个或一个。

Answer 1

试试这个：

select Name from Property where id in (select property_id from Property_Options where Property_Option = 'terrace ' and Property_Option = 'balcony ' and Property_Option = 'garaj')a

Answer 2

我会使用聚合和group by：

来完成此操作

select p.propertyid
from property p
group by p.propertyid
having sum(property_option = 'terrace') > 0 and
       sum(property_option = 'balcony') > 0 and
       sum(property_option = 'garaj') > 0;

每个条件都会计算属性出现的次数。这是一种灵活的方法。如果你想要前两个，而不是“garaj”，你会使用：

having sum(property_option = 'terrace') > 0 and
       sum(property_option = 'balcony') > 0 and
       sum(property_option = 'garaj') = 0;

Answer 3

这是确切的答案

从属性p选择p.id，p.name INNER JOIN property_option po on p.id = po.property_id group by p.id 总和（po.meta_name ='terrace'）＆gt; 0和sum（po.meta_name ='balcony'）＆gt; 0和sum（po.meta_name ='garaj'）＆gt; 0

需要一对多关系的Mysql Query才能进行匹配搜索

3 个答案: