当我有一个空字段或用户名错误或不匹配时，我似乎无法验证。请任何帮助或指点我会非常有帮助。我试过（空但是当我填写一个字段而另一个是空的时它似乎没有工作，它说所有字段都是空的。并且对于错误的凭据它根本不起作用。
的index.php
<?php
session_start();
include_once 'php/classes/class.user.php';
$user = new User();
$log = $_SESSION['uid'];
if ($user->get_session($log)){
header("Location: profile.php?uid=".$log."");
}
if (isset($_REQUEST['submit'])) {
extract($_REQUEST);
$login = $user->check_login($emailusername, $password);
if(!empty($login)){
if($emailusername != $login){
if($password != $login){
if ($login) {
// Registration Success
$log_id = $_SESSION['uid'];
header("location: profile.php?uid=".$log_id."");
}
}else
echo "Incorrect Password";
}else
echo "Incorrect Email";
}else
echo "Fill in fields";
}
?>
USERS.PHP
<?php
include "db_config.php";
class User{
public $db;
public function __construct(){
$this->db = new mysqli(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
if(mysqli_connect_errno()) {
echo "Error: Could not connect to database.";
exit;
}
}
/*** for login process ***/
public function check_login($emailusername, $password){
$password = md5($password);
$sql2="SELECT uid from users WHERE uemail='$emailusername' or uname='$emailusername' and upass='$password'";
//checking if the username is available in the table
$result = mysqli_query($this->db,$sql2);
$user_data = mysqli_fetch_array($result);
$count_row = $result->num_rows;
if ($count_row == 1) {
// this login var will use for the session thing
session_start();
$emaildb == $_SESSION['uemail'];
$_SESSION['login'] = true;
$_SESSION['uid'] = $user_data['uid'];
return true;
}
else{
return false;
}
}
/*** for showing the username or fullname ***/
public function get_fullname($uid){
$sql = "SELECT * FROM users WHERE uid = $uid";
$result = mysqli_query($this->db, $sql);
$user_data = mysqli_fetch_array($result);
echo $user_data['fullname'], "<br/>";
echo $user_data['uemail'], "<br/>";
echo $user_data['uid'], "<br/>";
}
public function check_user($uid){
$sql5 = "SELECT * from users WHERE uid='$uid'";
$result1 = mysqli_query($this->db, $sql5);
$count_row1 = $result1->num_rows;
return ($count_row1 == 1);
}
/*** starting the session ***/
public function get_session(){
return $_SESSION['login'];
}
public function user_logout() {
$_SESSION['login'] = FALSE;
session_destroy();
}
}
答案 0 :(得分：1)
根据你所拥有的，这就是你需要的。
session_start();
include_once 'php/classes/class.user.php';
$user = new User();
// You need a conditional incase this session isn't set
$log = (isset($_SESSION['uid']))? $_SESSION['uid']:false;
if($log !== false && $user->get_session($log)){
header("Location: profile.php?uid=".$log."");
exit;
}
if(isset($_POST['submit'])) {
// This function should be validating your login so you don't need
// any comparisons after the fact.
$login = $user->check_login($_POST['email'], $_POST['password']);
if($login !== false)
header("location: profile.php?uid=".$log_id."");
exit;
else {
foreach($user->error as $kind => $err) {
echo '<h2>'.$kind.'</h2>'.'<p>'.$err.'</p>';
}
}
}
您的用户类：如果您愿意，可以将错误报告投放到此课程中。
class User{
public $db;
public $error;
public function __construct(){
$this->db = new mysqli(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
if(mysqli_connect_errno()) {
$this->error['db'] = "Error: Could not connect to database.";
echo $this->error['db'];
exit;
}
}
/*** for login process ***/
public function check_login($emailusername='', $password=''){
// Validate that your email is a real one
if(filter_var($emailusername,FILTER_VALIDATE_EMAIL) !== false) {
$password = md5($password);
// --> You can prepare, bind, and execute your values here replacing what you have now....<--
$sql2 = "SELECT uid from users WHERE uemail='$emailusername' or uname='$emailusername' and upass='$password'";
//checking if the username is available in the table
$result = mysqli_query($this->db,$sql2);
$user_data = mysqli_fetch_array($result);
$count_row = $result->num_rows;
if ($count_row == 1) {
$emaildb == $_SESSION['uemail'];
// this login var will use for the session thing
$_SESSION['username'] = $user_data['uemail'];
// $_SESSION['uemail'] = $user_data['uemail'];
$_SESSION['uid'] = $user_data['uid'];
$_SESSION['login'] = true;
}
else
$this->error['account'] = 'ERROR: Invalid Username/Password';
}
else
$this->error['email'] = 'ERROR: Invalid Email Address';
return (!isset($_SESSION['uemail']))? false:true;
}
/*** for showing the username or fullname ***/
public function get_fullname($uid){
// --> You can prepare, bind, and execute your values here replacing what you have now....<--
$sql = "SELECT * FROM users WHERE uid = $uid";
$result = mysqli_query($this->db, $sql);
$user_data = mysqli_fetch_array($result);
echo $user_data['fullname'], "<br/>";
echo $user_data['uemail'], "<br/>";
echo $user_data['uid'], "<br/>";
}
public function check_user($uid){
// --> You can prepare, bind, and execute your values here replacing what you have now....<--
$sql5 = "SELECT * from users WHERE uid='$uid'";
$result1 = mysqli_query($this->db, $sql5);
$count_row1 = $result1->num_rows;
return ($count_row1 == 1);
}
/*** starting the session ***/
public function get_session(){
return $_SESSION['login'];
}
public function user_logout() {
$_SESSION['login'] = FALSE;
session_destroy();
}
}
答案 1 :(得分：-1)
$login是一个布尔变量，而$emailusername和$password是字符串，为什么要比较它们。