对不起我是sql世界的新手，这个声明的结账时间与结账时间不同，并且从声明中删除checkinorout，如你所见：
SELECT
USERINFO.Badgenumber AS USERID,
CHECKINOUT.CHECKTIME AS Checkin,
CHECKINOUT.CHECKTIME AS Checkout,
Machines.MachineAlias,
CHECKINOUT.checkinorout
FROM CHECKINOUT
INNER JOIN USERINFO ON CHECKINOUT.USERID = USERINFO.USERID
INNER JOIN Machines ON CHECKINOUT.SENSORID = Machines.MachineNumber
WHERE (CHECKINOUT.CHECKTIME > '2014-09-25 00:00:00.000')
order by checkin
输出：
USERID Checkin Checkout Machines checkinorout
32 2014-09-25 09:12:57.000 2014-09-25 09:12:57.000 HQ Checkin
32 2014-09-25 12:58:51.000 2014-09-25 12:58:51.000 HQ CheckOut
32 2014-09-26 18:03:33.000 2014-09-26 18:03:33.000 HQ Checkin
32 2014-09-26 22:03:11.000 2014-09-26 22:03:11.000 HQ CheckOut
32 2014-09-27 12:57:55.000 2014-09-27 12:57:55.000 HQ Checkin
32 2014-09-27 17:01:32.000 2014-09-27 17:01:32.000 HQ CheckOut
32 2014-09-28 13:05:03.000 2014-09-28 13:05:03.000 HQ Checkin
32 2014-09-28 17:35:29.000 2014-09-28 17:35:29.000 HQ CheckOut
32 2014-09-29 09:18:12.000 2014-09-29 09:18:12.000 HQ Checkin
32 2014-09-29 18:10:43.000 2014-09-29 18:10:43.000 HQ CheckOut
32 2014-09-30 09:12:13.000 2014-09-30 09:12:13.000 HQ Checkin
我需要输出像这样
USERID Checkin Checkout Machines
32 2014-09-25 09:12:57.000 2014-09-25 12:58:51.000 HQ
32 2014-09-26 18:03:33.000 2014-09-26 22:03:11.000 HQ
32 2014-09-27 12:57:55.000 2014-09-27 17:01:32.000 HQ
32 2014-09-28 13:05:03.000 2014-09-28 17:35:29.000 HQ
32 2014-09-29 09:18:12.000 2014-09-29 18:10:43.000 HQ
感谢MR @sgeddes，但是当我编辑你的陈述以获得结果时
with cte as (
select *,
row_number() over (partition by userid, checkinorout order by CHECKTIME) rn
from CHECKINOUT
)
select userid,
max(case when checkinorout = 'checkin' then CHECKTIME end) checkin,
max(case when checkinorout = 'checkout' then CHECKTIME end) checkout
from cte where USERID=15 and CHECKTIME between '2014-9-21 00:00:00.000' and '2014-10-25 00:00:00.000'
group by userid , rn
userid checkin checkout
15 NULL 2014-09-21 18:50:24.000
15 NULL 2014-09-22 18:06:15.000
15 NULL 2014-09-23 18:01:30.000
15 NULL 2014-09-24 16:52:36.000
15 NULL 2014-09-25 12:58:51.000
15 NULL 2014-09-26 22:03:11.000
15 NULL 2014-09-27 17:01:32.000
15 NULL 2014-09-28 17:35:29.000
15 NULL 2014-09-29 18:10:43.000
15 NULL 2014-09-30 18:11:19.000
15 NULL 2014-10-01 17:52:49.000
15 NULL 2014-10-12 20:13:10.000
15 2014-09-21 10:17:24.000 2014-10-13 22:13:11.000
15 2014-09-22 09:18:29.000 2014-10-14 21:49:28.000
15 2014-09-23 09:10:15.000 2014-10-15 10:14:09.000
15 2014-09-24 09:43:27.000 2014-10-16 17:55:06.000
15 2014-09-25 09:12:57.000 2014-10-17 23:17:00.000
15 2014-09-26 18:03:33.000 2014-10-20 12:38:22.000
15 2014-09-27 12:57:55.000 2014-10-21 07:31:39.000
15 2014-09-28 13:05:03.000 2014-10-22 05:51:47.000
15 2014-09-29 09:18:12.000 2014-10-24 11:26:06.000
15 2014-09-30 09:12:13.000 NULL
15 2014-10-01 10:16:59.000 NULL
15 2014-10-02 10:13:52.000 NULL
15 2014-10-03 00:59:18.000 NULL
15 2014-10-11 22:07:06.000 NULL
15 2014-10-12 09:58:34.000 NULL
15 2014-10-13 05:09:34.000 NULL
15 2014-10-14 11:42:58.000 NULL
15 2014-10-15 04:48:27.000 NULL
15 2014-10-15 15:49:06.000 NULL
15 2014-10-16 09:14:21.000 NULL
15 2014-10-16 21:14:18.000 NULL
15 2014-10-17 00:59:57.000 NULL
15 2014-10-18 17:42:26.000 NULL
15 2014-10-20 01:22:01.000 NULL
15 2014-10-21 01:24:30.000 NULL
15 2014-10-22 00:10:34.000 NULL
15 2014-10-23 20:01:02.000 NULL
15 2014-10-24 01:08:51.000 NULL
我需要它
userid checkin checkout
15 2014-09-21 10:17:24.000 2014-09-21 18:50:24.000
15 2014-09-22 09:18:29.000 2014-09-22 18:06:15.000
15 2014-09-23 09:10:15.000 2014-09-23 18:01:30.000
15 2014-09-24 09:43:27.000 2014-09-24 16:52:36.000
15 2014-09-25 09:12:57.000 2014-09-25 12:58:51.000
15 2014-09-26 18:03:33.000 2014-09-26 22:03:11.000
15 2014-09-27 12:57:55.000 2014-09-27 17:01:32.000
谢谢@slavoo先生
我尝试时拥有的东西......
SELECT
u.Badgenumber AS USERID,
c.CHECKTIME AS Checkout,
checkingOut.time AS Checkin,
m.MachineAlias
FROM CHECKINOUT c
INNER JOIN USERINFO u ON c.USERID = u.USERID
INNER JOIN Machines m ON c.SENSORID = m.MachineNumber
OUTER APPLY
(
SELECT top 1 c2.CHECKTIME as time FROM CHECKINOUT c2
WHERE c2.checkinorout = 'Checkout'
AND c.USERID = c2.USERID
AND c.SENSORID = c2.SENSORID
AND c.CHECKTIME < c2.CHECKTIME
order by c2.CHECKTIME asc
) as checkingOut
WHERE (c.CHECKTIME between '2014-10-19 00:00:00.000' and '2014-10-27 00:00:00.000' )
and u.Badgenumber=660
AND c.checkinorout = 'Checkin'
AND checkingOut.time is not null
order by checkingOut.time
输出：
USERID Checkout Checkin MachineAlias
660 2014-10-19 01:56:47.000 2014-10-19 17:27:41.000 Branch4
660 2014-10-20 02:00:14.000 2014-10-20 17:39:35.000 Branch4
660 2014-10-21 01:55:49.000 2014-10-21 16:57:22.000 Branch4
660 2014-10-22 01:59:23.000 2014-10-25 16:48:29.000 Branch4
660 2014-10-23 16:59:34.000 2014-10-25 16:48:29.000 Branch4
660 2014-10-24 16:58:36.000 2014-10-25 16:48:29.000 Branch4
660 2014-10-25 01:56:47.000 2014-10-25 16:48:29.000 Branch4
我需要它
USERID Checkout Checkin MachineAlias
660 2014-10-20 02:00:14.000 2014-10-19 17:27:41.000 Branch4
660 2014-10-21 01:55:49.000 2014-10-20 17:39:35.000 Branch4
660 2014-10-22 01:59:23.000 2014-10-21 16:57:22.000 Branch4
660 Null 2014-10-23 16:59:34.000 Branch4
660 2014-10-25 01:56:47.000 2014-10-24 16:58:36.000 Branch4
660 2014-10-26 00:55:35.000 2014-10-25 16:48:29.000 Branch4
这是我从中读取的表
select USERID ,CHECKTIME,checkinorout from CHECKINOUT where USERID=80 and CHECKTIME between '2014-10-19 00:00:00.000' and '2014-10-27 00:00:00.000'
order by CHECKTIME
这是此用户的完整交易
80 2014-10-19 01:56:47.000 Checkin
80 2014-10-19 17:27:41.000 CheckOut
80 2014-10-20 02:00:14.000 Checkin
80 2014-10-20 17:39:35.000 CheckOut
80 2014-10-21 01:55:49.000 Checkin
80 2014-10-21 16:57:22.000 CheckOut
80 2014-10-22 01:59:23.000 Checkin
80 2014-10-23 16:59:34.000 Checkin
80 2014-10-24 16:58:36.000 Checkin
80 2014-10-25 01:56:47.000 Checkin
80 2014-10-25 16:48:29.000 CheckOut
80 2014-10-26 00:55:35.000 Checkin
为您的笔记我有脚本更新签入或退出checkinorout列
要知道此报告是指纹签入和签出报告 如果他发现没有办理登机手续，请将其保留为空，如果他发现结账为空，则将其保留为空（此雇员在下午5:00:00进行轮班检查，并在凌晨2:00:00退房）;
答案 0 :(得分：1)
您可以使用ROW_NUMBER()在签到和结帐之间建立分组。然后，您需要转移结果 - 您可以MAX使用CASE来执行此操作：
这是使用公用表表达式的简化版本：
with cte as (
select *,
row_number() over (partition by userid, checkinorout order by checkin) rn
from results
)
select userid,
max(case when checkinorout = 'checkin' then checkin end) checkin,
max(case when checkinorout = 'checkout' then checkout end) checkout,
machines
from cte
group by userid, machines, rn
编辑，鉴于您的评论，您是否可以使用HAVING子句删除NULL条记录？
having max(case when checkinorout = 'checkin' then checkin end) is not null
and max(case when checkinorout = 'checkout' then checkout end) is not null
答案 1 :(得分：1)
SELECT
u.Badgenumber AS USERID,
c.CHECKTIME AS Checkin,
checkingOut.time AS Checkout,
m.MachineAlias
FROM CHECKINOUT c
INNER JOIN users u ON c.USERID = u.USERID
INNER JOIN Machines m ON c.SENSORID = m.MachineNumber
OUTER APPLY
(
SELECT top 1 c2.CHECKTIME as time FROM CHECKINOUT c2
WHERE c2.checkinorout = 'Checkout'
AND c.USERID = c2.USERID
AND c.SENSORID = c2.SENSORID
AND c.CHECKTIME < c2.CHECKTIME
AND CAST(c.CHECKTIME as DATE) = CAST(c2.CHECKTIME as DATE)
order by c2.CHECKTIME asc
) as checkingOut
WHERE (c.CHECKTIME > '2014-09-25 00:00:00.000')
AND c.checkinorout = 'Checkin'
order by checkin
或者这个：
SELECT
u.Badgenumber AS USERID,
c.CHECKTIME AS Checkin,
checkingOut.time AS Checkout,
Machines.MachineAlias
FROM CHECKINOUT c
INNER JOIN users u ON c.USERID = u.USERID
INNER JOIN Machines ON c.SENSORID = Machines.MachineNumber
OUTER APPLY
(
SELECT top 1 c2.CHECKTIME as time FROM CHECKINOUT c2
WHERE c2.checkinorout = 'Checkout'
AND c.USERID = c2.USERID
AND c.SENSORID = c2.SENSORID
AND c.CHECKTIME < c2.CHECKTIME
AND NOT EXISTS (SELECT * FROM CHECKINOUT c3
WHERE c3.checkinorout = 'Checkin'
AND c3.USERID = c2.USERID
AND c3.SENSORID = c2.SENSORID
AND c3.CHECKTIME > c.CHECKTIME
AND c3.CHECKTIME < c2.CHECKTIME)
order by c2.CHECKTIME asc
) as checkingOut
WHERE (c.CHECKTIME > '2014-09-25 00:00:00.000')
AND c.checkinorout = 'Checkin'
order by checkin