出于某种原因,我无法在下图的实现中查找正确的键。由于出现错误的字典实现,我一直得到一个KeyError。我已经研究了几个小时,仍然无法弄清楚问题是什么。
> KeyError Traceback (most recent call
> last)
> C:\Users\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.4.0.1938.win-x86_64\lib\site-packages\IPython\utils\py3compat.pyc
> in execfile(fname, glob, loc)
> 195 else:
> 196 filename = fname
> --> 197 exec compile(scripttext, filename, 'exec') in glob, loc
> 198 else:
> 199 def execfile(fname, *where):
>
> C:\Users\ps5.py in <module>()
> 69
> 70
> ---> 71 bigMap = load_map(mapFile)
> 72
>
> C:\Users\ps5.py in load_map(mapFilename)
> 51 e1 = WeightedEdge(nx, ny, ex, ey)
> 52
> ---> 53 g.addEdge(e1)
> 54 return g
> 55
>
> C:\Users\graph.py in addEdge(self, edge)
> 74 if not (src.getName() in self.nodes and dest.getName() in self.nodes):
> 75 raise ValueError('Node not in graph')
> ---> 76 self.edges[src].append([dest, (edge.getTotalDistance(), edge.getOutdoorDistance())])
> 77
> 78 def __str__(self):
>
> KeyError: <graph.Node object at 0x00000000080B1A90>
class Node(object):
def __init__(self, name):
self.name = str(name)
def getName(self):
return self.name
def __str__(self):
return self.name
class Edge(object):
def __init__(self, src, dest):
self.src = src
self.dest = dest
def getSource(self):
return self.src
def getDestination(self):
return self.dest
def __str__(self):
return str(self.src) + '->' + str(self.dest)
class WeightedEdge(Edge):
def __init__(self, src, dest, totalDistance, outdoorDistance):
self.src = src
self.dest = dest
self.totalDistance = float(totalDistance)
self.outdoorDistance = float(outdoorDistance)
def getWeight(self):
return self.weight
def __str__(self):
return str(self.src) + '->' + str(self.dest) + ' (' + \
str(self.totalDistance) + ', ' + str(self.outdoorDistance) + ')'
def getTotalDistance(self):
return self.totalDistance
def getOutdoorDistance(self):
return self.outdoorDistance
class Digraph(object):
def __init__(self):
self.nodes = set([])
self.edges = {}
def addNode(self, node):
if node.getName() in self.nodes:
raise ValueError('Duplicate node')
else:
self.nodes.add(node.getName())
self.edges[node] = []
def addEdge(self, edge):
src = edge.getSource()
dest = edge.getDestination()
if not(src in self.nodes and dest in self.nodes):
raise ValueError('Node not in graph')
self.edges[src].append(dest)
def childrenOf(self, node):
return self.edges[node]
def hasNode(self, node):
return str(node) in self.nodes
def __str__(self):
res = ''
for k in self.edges:
for d in self.edges[k]:
res = res + str(k) + '->' + str(d) + '\n'
return res[:-1]
class Graph(Digraph):
def addEdge(self, edge):
Digraph.addEdge(self, edge)
rev = Edge(edge.getDestination(), edge.getSource())
Digraph.addEdge(self, rev)
class WeightedDigraph(Digraph):
def addEdge(self, edge):
src = edge.getSource()
dest = edge.getDestination()
if not (src.getName() in self.nodes and dest.getName() in self.nodes):
raise ValueError('Node not in graph')
self.edges[src].append([dest, (edge.getTotalDistance(), edge.getOutdoorDistance())])
def __str__(self):
res = ''
for k in self.edges:
for d in self.edges[k]:
res = res + str(k) + '->' + str(d[0]) + ' (' + str(float(d[1][0])) + ', ' + str(float(d[1][1])) + ')' + '\n'
return res[:-1]
def childrenOf(self, node):
children = []
for child in self.edges[node]:
children.append(child[0])
return children
def load_map(mapFilename):
dataFile = open(mapFilename, 'r')
g = WeightedDigraph()
for line in dataFile:
nx, ny, ex, ey = line.split()
nx = Node(nx)
ny = Node(ny)
if not g.hasNode(nx):
g.addNode(nx)
if not g.hasNode(ny):
g.addNode(ny)
e1 = WeightedEdge(nx, ny, ex, ey)
g.addEdge(e1)
return g
bigMap = load_map(mapFile)
答案 0 :(得分:1)
因此,您的错误似乎在WeightedDigraph.addEdge(self, edge)
。
您传入一个边缘对象并获取源(src = edge.getSource()
)。通过使用调试器,我能够查看字典self.edges
,我发现密钥的格式为{<Node object>: <list>}
。
实际的调试视图给了我这个:
self.edges = { <__main__.Node object at 0x10f1d4350>: [] }
如果您要将对象用作python dict中的键,则需要包含两个函数:
def __hash__(self)
和
def __eq__(self, other)
这是一个堆栈溢出问题,可以解决这个问题:Object of custom type as dictionary key
我做了一个快速标记,它似乎解决了你的密钥错误。
此外,我强烈建议使用调试器(pydb(http://bashdb.sourceforge.net/pydb/)是一个这样的调试器,但很多内置在IDE中),因为这是我发现错误的方法。