Question

我很困惑！我有3个表，分别给我我正在寻找的结果。当我加入他们（尝试加入，联合，左联接，子查询）时，我得到了偏差的结果。

表1：

SELECT DISTINCT JB.job_id, AR.job_id as jid, SUM(AR.ar_payment_amount) AS sum,
JB.marketing_campaign FROM job_tbl JB LEFT JOIN ar_payment_tbl AR ON JB.job_id = 
AR.job_id WHERE JB.marketing_campaign != '' AND FROM_UNIXTIME(AR.ar_payment_date,'%Y') = 
YEAR(NOW()) GROUP BY JB.marketing_campaign ORDER BY sum DESC LIMIT 10

这给了我正在寻找的结果（只显示了这个例子的一个结果）

[job_id] => 551
[jid] => 551
[sum] => 124440.97024536133
[marketing_campaign] => Roto Rooter

表2：

SELECT DISTINCT JB.job_id, AP.job_id, SUM(price) AS price, AP.vendor FROM job_tbl JB 
LEFT JOIN ap_tbl AP ON JB.job_id = AP.job_id WHERE AP.marked_as_paid = 1 AND 
AP.activity = 'Commission' AND FROM_UNIXTIME(AP.payment_date,'%Y') = YEAR(NOW()) GROUP
BY vendor ORDER BY price DESC LIMIT 10

这给了我正在寻找的结果......

        [job_id] => 551
        [price] => 5700
        [vendor] => 436

现在当我加入他们时，我得到了不同的结果

SELECT DISTINCT JB.job_id, AR.job_id as arid, AP.job_id as apid, 
SUM(AR.ar_payment_amount) AS sum, SUM(AP.price) AS price, JB.marketing_campaign FROM
job_tbl JB LEFT JOIN ap_tbl AP ON JB.job_id = AP.job_id AND AP.marked_as_paid = 1 AND 
AP.activity = 'Commission' LEFT JOIN ar_payment_tbl AR ON JB.job_id = AR.job_id  AND 
FROM_UNIXTIME(AR.ar_payment_date,'%Y') = YEAR(NOW()) WHERE AP.price != '' AND 
AR.ar_payment_amount != '' AND JB.marketing_campaign != '' GROUP BY 
JB.marketing_campaign ORDER BY sum DESC LIMIT 10

以下是我得到的结果

        [job_id] => 551
        [arid] => 551
        [apid] => 551
        [sum] => 130507.02011108398
        [price] => 8200
        [marketing_campaign] => Roto Rooter

以及结果应该是

        [job_id] => 551
        [arid] => 551
        [apid] => 551
        [sum] => 124440.97024536133
        [price] => 5700
        [marketing_campaign] => Roto Rooter

任何帮助将不胜感激，这个项目上周五到期！ ; - ）

Answer 1

试试这个 - 我认为JOIN条件和GROUP BY存在问题：

SELECT 
    JB.job_id, 
    AR.job_id as arid, 
    AP.job_id as apid, 
    JB.marketing_campaign,
    SUM(AR.ar_payment_amount) AS `sum`, 
    SUM(AP.price) AS price

FROM job_tbl JB 
LEFT JOIN ap_tbl AP ON JB.job_id = AP.job_id 
LEFT JOIN ar_payment_tbl AR ON JB.job_id = AR.job_id
WHERE
    AP.marked_as_paid = 1 
    AND AP.activity = 'Commission'   
    AND FROM_UNIXTIME(AR.ar_payment_date,'%Y') = YEAR(NOW()) 
    AND AP.price != '' 
    AND AR.ar_payment_amount != '' 
    AND JB.marketing_campaign != '' 
GROUP BY 1,2,3,4
ORDER BY `sum` DESC LIMIT 10

独特的左连接带来了偏差的结果

1 个答案: