我需要帮助弄清楚如何计算胜利，失败和关系的记录。现在，代码返回字符串＆＃34; loss＆＃34;当球员输球时我希望它返回1，一次丢失。有人可以帮忙吗？这是我到目前为止的代码。
# Tic Tac Toe
import random
def score():
wins = 0
losses = 0
ties = 0
def result(wins, losses, ties):
if result =='win':
wins += 1
if result == 'loss':
losses += 1
else:
ties += 1
def drawBoard(board):
# This function prints out the board that it was passed.
# "board" is a list of 10 strings representing the board (ignore index 0)
print(' | |')
print(' ' + board[7] + ' | ' + board[8] + ' | ' + board[9])
print(' | |')
print('-----------')
print(' | |')
print(' ' + board[4] + ' | ' + board[5] + ' | ' + board[6])
print(' | |')
print('-----------')
print(' | |')
print(' ' + board[1] + ' | ' + board[2] + ' | ' + board[3])
print(' | |')
def inputPlayerLetter():
# Let's the player type which letter they want to be.
# Returns a list with the player's letter as the first item, and the computer's letter as the second.
letter = ''
while not (letter == 'X' or letter == 'O'):
print('Do you want to be X or O?')
letter = input().upper()
# the first element in the tuple is the player's letter, the second is the computer's letter.
if letter == 'X':
return ['X', 'O']
else:
return ['O', 'X']
def whoGoesFirst():
# Randomly choose the player who goes first.
if random.randint(0, 1) == 0:
return 'computer'
else:
return 'player'
def playAgain():
# This function returns True if the player wants to play again, otherwise it returns False.
print('Do you want to play again? (yes or no)')
return input().lower().startswith('y')
def makeMove(board, letter, move):
board[move] = letter
def isWinner(bo, le):
# Given a board and a player's letter, this function returns True if that player has won.
# We use bo instead of board and le instead of letter so we don't have to type as much.
return ((bo[7] == le and bo[8] == le and bo[9] == le) or # across the top
(bo[4] == le and bo[5] == le and bo[6] == le) or # across the middle
(bo[1] == le and bo[2] == le and bo[3] == le) or # across the bottom
(bo[7] == le and bo[4] == le and bo[1] == le) or # down the left side
(bo[8] == le and bo[5] == le and bo[2] == le) or # down the middle
(bo[9] == le and bo[6] == le and bo[3] == le) or # down the right side
(bo[7] == le and bo[5] == le and bo[3] == le) or # diagonal
(bo[9] == le and bo[5] == le and bo[1] == le)) # diagonal
def getBoardCopy(board):
# Make a duplicate of the board list and return it the duplicate.
dupeBoard = []
for i in board:
dupeBoard.append(i)
return dupeBoard
def isSpaceFree(board, move):
# Return true if the passed move is free on the passed board.
return board[move] == ' '
def getPlayerMove(board):
# Let the player type in his move.
move = ' '
while move not in '1 2 3 4 5 6 7 8 9'.split() or not isSpaceFree(board, int(move)):
print('What is your next move? (1-9)')
move = input()
return int(move)
def chooseRandomMoveFromList(board, movesList):
# Returns a valid move from the passed list on the passed board.
# Returns None if there is no valid move.
possibleMoves = []
for i in movesList:
if isSpaceFree(board, i):
possibleMoves.append(i)
if len(possibleMoves) != 0:
return random.choice(possibleMoves)
else:
return None
def getComputerMove(board, computerLetter):
# Given a board and the computer's letter, determine where to move and return that move.
if computerLetter == 'X':
playerLetter = 'O'
else:
playerLetter = 'X'
# Here is our algorithm for our Tic Tac Toe AI:
# First, check if we can win in the next move
for i in range(1, 10):
copy = getBoardCopy(board)
if isSpaceFree(copy, i):
makeMove(copy, computerLetter, i)
if isWinner(copy, computerLetter):
return i
# Check if the player could win on his next move, and block them.
for i in range(1, 10):
copy = getBoardCopy(board)
if isSpaceFree(copy, i):
makeMove(copy, playerLetter, i)
if isWinner(copy, playerLetter):
return i
# Try to take one of the corners, if they are free.
move = chooseRandomMoveFromList(board, [1, 3, 7, 9])
if move != None:
return move
# Try to take the center, if it is free.
if isSpaceFree(board, 5):
return 5
# Move on one of the sides.
return chooseRandomMoveFromList(board, [2, 4, 6, 8])
def isBoardFull(board):
# Return True if every space on the board has been taken. Otherwise return False.
for i in range(1, 10):
if isSpaceFree(board, i):
return False
return True
print('Welcome to Tic Tac Toe!')
while True:
# Reset the board
theBoard = [' '] * 10
playerLetter, computerLetter = inputPlayerLetter()
turn = whoGoesFirst()
print('The ' + turn + ' will go first.')
gameIsPlaying = True
while gameIsPlaying:
if turn == 'player':
# Player's turn.
drawBoard(theBoard)
move = getPlayerMove(theBoard)
makeMove(theBoard, playerLetter, move)
if isWinner(theBoard, playerLetter):
drawBoard(theBoard)
result = 'win'
print('Hooray! You have won the game!')
isWinner = True
gameIsPlaying = False
else:
if isBoardFull(theBoard):
drawBoard(theBoard)
result = 'tie'
print('The game is a tie!')
break
else:
turn = 'computer'
else:
# Computer's turn.
move = getComputerMove(theBoard, computerLetter)
makeMove(theBoard, computerLetter, move)
if isWinner(theBoard, computerLetter):
drawBoard(theBoard)
print('The computer has beaten you! You lose.')
result = 'loss'
isWinner = False
gameIsPlaying = False
else:
if isBoardFull(theBoard):
drawBoard(theBoard)
result = 'tie'
print('The game is a tie!')
break
else:
turn = 'player'
if not playAgain():
print(result)
break
答案 0 :(得分：0)
您可以在开始时和重置时设置result = 'win'，而不是执行wins = 0，当玩家获胜时，只需wins += 1。对ties和losses执行相同操作，然后您可以从以wins，losses和ties作为参数的函数中提取完整记录。
答案 1 :(得分：0)
您的功能score()和result(wins, loses, ties)肯定无法正常运作。
函数中的所有变量都是局部变量，因此该代码将打印10而不是11：
def make_bigger(x):
x += 1
X = 10
make_bigger(X)
print(x)
您可能需要使用以下函数来代替使用该函数：
def pr_score(win, lose, tie):
print('Score:')
print('\twin:', win)
print('\tlose:', lose)
print('\ttie:', tie)
对于赢/输/领带计数，您需要添加：
win = 0
lose = 0
tie = 0
while True:之前。
您还应该在win += 1语句中添加if isWinner(theBoard, playerLetter):，在tie += 1语句中添加if isBoardFull(theBoard):。
关于计算机转弯的代码也应如下所示：
if isBoardFull(theBoard):
drawBoard(theBoard)
result = 'tie'
print('The game is a tie!')
else:
# Computer's turn.
move = getComputerMove(theBoard, computerLetter)
makeMove(theBoard, computerLetter, move)
turn = 'player'
if isWinner(theBoard, computerLetter):
drawBoard(theBoard)
print('The computer has beaten you! You lose.')
result = 'loss'
lose += 1
isWinner = False
gameIsPlaying = False
if isBoardFull(theBoard):
drawBoard(theBoard)
result = 'tie'
print('The game is a tie!')
break
对于打印结果，您应在pr_score(win, lose, tie)中添加if not playAgain():。
如果你希望能够进行另一轮上一轮break的缩进。
此外，如果您在getPlayerMove(board)之后的move = input()中添加这些行：
if move not in '1 2 3 4 5 6 7 8 9'.split(): #input is incorrect
print('Input is incorrect.\nPlease write nuber!')
elif not isSpaceFree(board, int(move)): #that place isn't free
print('That place is already taken.\nPlease take free place!')
以及while True之前的这些行：
exampleBoard = [' ']
for x in range(1, 10):
exampleBoard.append(str(x))
drawBoard(exampleBoard)
对用户有用。