Question

private void sendData（String message）{ byte [] msgBuffer = message.getBytes（）;

    Log.d(TAG, "...Send data: " + message + "...");

    try {
        outStream.write(msgBuffer);

    } catch (IOException e) {
        String msg = "In onResume() and an exception occurred during write: "
                + e.getMessage();
        if (address.equals("00:00:00:00:00:00"))
            msg = msg
                    + ".\n\nUpdate your server address from 00:00:00:00:00:00 to the correct address on line 35 in the java code";
        msg = msg + ".\n\nCheck that the SPP UUID: " + MY_UUID.toString()
                + " exists on server.\n\n";

        errorExit("Fatal Error", msg);
    }
}

在上面的代码中，我们可以发送像“0”和“1”这样的数据。但是要发送像00000000和00000001这样的8位。它应该显示在Arduino板上。如果按下发送数据1，则应显示00000001和00000000。

Answer 1

使用此：

String str = "25789";
    int i = Integer.parseInt(str);
    String binarystr = Integer.toBinaryString(i); 

    char[] buffer = new char[binarystr.length()];
    binarystr.getChars(0,binarystr.length(), buffer, 0);

    System.out.println("char array:: "+Arrays.toString(buffer));

    byte[] binaryFormat = getbyteFromString(buffer);


    for (byte b : binaryFormat) {
        System.out.println(Integer.toBinaryString(b & 255 | 256).substring(1));
    }

方法：

private byte[] getbyteFromString(char[] binarystr){
int length = binarystr.length/8;

if(binarystr.length % 8 > 0)
    length++;

int iterationCount = length ;

byte[] binaryFormat = new byte[iterationCount];
int iter = iterationCount - 1;


for(int i = binarystr.length - 1; i >=0 ;){

    byte byt = 0x0;
    for(int j = 0; j < 8 ; j++){

        if(i < 0)
            break;

        int b = binarystr[i] - 48;
        byt = (byte) (byt + (b << j));
        i--;
    }

    binaryFormat[iter] = byt;

    iter--;
}

return binaryFormat;

}

arduino以二进制格式（二进制数据包）而不是1和0发送数据。发送方式如00000000和00000001（8位二进制）

1 个答案: