Question

因此，在对@ Jean-PaulCalderone的大量耐心和感激之后，我现在有了一个支持（尚待测试）TLS的扭曲邮件服务器！我可以telnet到它，发出我的EHLO，MAIL FROM等，并根据下面的代码片段将消息转储到文件中（以下2个类从http://twistedmatrix.com/documents/current/_downloads/emailserver.tac翻录和修改：

class ConsoleMessageDelivery:
    implements(smtp.IMessageDelivery)

    def receivedHeader(self, helo, origin, recipients):
        by = helo[1]
        from_ = origin
        for_ = "%s" % (' '.join(map(str, recipients)))
        return "Client: %s\nFrom: %s\nTo: %s\n\n" % (by, from_, for_)

    def validateFrom(self, helo, origin):
        return origin

    def validateTo(self, user):
        return lambda: ConsoleMessage()


class ConsoleMessage:
    implements(smtp.IMessage)

    def __init__(self):
        self.lines = []

    def lineReceived(self, line):
        self.lines.append(line)

    def eomReceived(self):
        print "New message received:"
        print "\n".join(self.lines)
        msgFile = open("./test.msg","w")
        msgFile.writelines(self.lines)
        msgFile.close()
        self.lines = None
        return defer.succeed(None)

    def connectionLost(self):
        # There was an error, throw away the stored lines
        self.lines = None

但是，当我指定多个RCPT TO地址时，问题就出现了 - 只有最后一个在我的receiveheader方法中的“收件人”中？我在“receivedHeader”中处理不当吗？我开始认为它是我的validateTo函数中的return语句。当我向2个收件人发送单个邮件时，服务器日志如下所示：

2014-10-21 08:05:10+0000 [ESMTP,2,127.0.0.1] Receiving message for delivery: from=me@home.com to=['you@work1.com', 'you@work2.com']
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] New message received:
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] Client: 127.0.0.1
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] From: me@home.com
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] To: you@work1.com
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] Today is the 21st Oct
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] (still)
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] New message received:
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] Client: 127.0.0.1
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] From: me@home.com
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] To: you@work2.com
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1]
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] Today is the 21st Oct
2014-10-21 08:05:17+0000 [ESMTP,2,127.0.0.1] (still)

此外，能够访问“完整”SMTP标头 - 消息ID等等将是件好事。我当然看了smtp.IMessage / smtp.IMessageDelivery的API文档 - 但看不出任何相关内容？最终，创建一个文件（可能是2，拆分标题/正文）会很好，名称基于msg ID ......

有人可以解释一下我缺少的东西吗？非常感谢！

Answer 1

您的代码和输出看起来非常好。不分组的收件人的行为是由于lambda语句触发self.lines.append()每个收件人/邮件的发送。

但是，您可以考虑更改lineReceived的行为，以便对收到的所有行进行分组。

祝你好运，希望这会有所帮助。

Twisted SMTP Server - 获取完整的收件人列表和标题数据？

1 个答案: