Question

这段代码就像这样工作

example.com/view.php?category=laptop&model=apple%20ipod

所以我想这样（删除空格）

example.com/view.php?category=laptop&model=appleipod

我该怎么做才能帮我解决这个问题，谢谢

      <?
$category = $_GET['category'];
$model = $_GET['model'];
    //connect to database

     mysql_connect('localhost','user','pass');
     mysql_select_db('datanew');


$result = mysql_query("SET NAMES utf8"); //the main trick
$q=mysql_query("select * from data where category='$category' And model='$model' AND TRIM(model) IS NOT NULL");

//Adds one to the counter
 mysql_query("UPDATE data SET counter = counter + 1 where category='$category' And model='$model'");

 //Retreives the current count
 $count = mysql_fetch_row(mysql_query("SELECT counter FROM data"));
$row=mysql_fetch_object($q);

echo mysql_error();


?>
<table class='hovertable'><?php if($row->model):?><tr class=\"style1\"><td width='200'><b>Model:</b></td><td><?php echo $row->model ?></td></tr><?php endif; ?>
<?php if($row->category):?><tr class=\"style1\"><td width='200'><b>Category:</b></td><td><?php echo $row->category?></td></tr><?php endif; ?></table>

Answer 1

<?php
  $model = str_replace(" ", "", $_GET['model']);
?>

Answer 2

（Auto. urldecode）使用str_replace(" ", "", $model);

但我建议在构建网址时进行工作。如果您要替换构建网址的空白，则可以使用str_replace(" ", "", $myModelName);。

Answer 3

使用replace_str替换所有空格

http://php.net/manual/en/function.str-replace.php

<?php
  $model = str_replace(" ", "", $_GET['model']);
?>

如何使用php删除获取id url中的空格

3 个答案: