Question

现在我遇到一个问题，用户会看到弹出窗口“更新成功”，如果他重新加载页面或向后到页面。任何人知道如何删除？id = 2后点击确定弹出？
这是我的代码：

update_action.php

$updresult = mysqli_query($conn, $sqlu);

    if (!$updresult)
        echo "Unable to update record". mysqli_error($conn);
    else
    {
        header('Location: index.php?id=2' );
        mysqli_close($conn);
    } 
    ?>

的index.php

if ($id == 1) 
    {
    ?>
        <script>
            alert("Invalid user name or password, Try again");
        </script>
    <?php   
    }
        else if($error_id == 2)
    {
    ?>
        <script>
            alert("Update Sucessfully!"); 
        </script>
    <?php
    }

the url show index.php?id=2

Answer 1

if ($id == 1) 
{
?>
    <script>
        alert("Invalid user name or password, Try again");
    </script>
<?php   
}
    else if($error_id == 2)
{
?>
    <script>
        alert("Update Sucessfully!"); 
 //---------- added ---------------
        window.location.href= 'index.php';
 //-------------------------

    </script>
<?php
}

Answer 2

您需要的是使用javascript更改网址而不重新加载网页。

退房：https://wiki.selfhtml.org/wiki/JavaScript/History/pushState

您可以在提醒/确认后将其放入

// Remove the "?.." from the url
var url = [location.protocol, '//', location.host, location.pathname].join('');
// maybe check if the browser supports history.pushState
history.pushState({}, '', url);

如何删除url中的id

2 个答案: