Question

我有一个表，在以这种格式执行每笔交易后存储客户余额：

Client number    balance     tran_date
7734766688       23000       07-AUG-2014
7734766688       40000       07-AUG-2014
7734766688       20000       10-AUG-2014
7734766688       13000       15-AUG-2014
7734766688      400000       29-AUG-2014
7734766688      200000       02-SEP-2014

客户不希望在8月12日到8月31日之间发表声明，这意味着期初余额为20000，截止到8月31日的期末余额为400000如何编写查询以获取如果可用日期仅在最后一次交易中，那么在查询日期和最后日期的余额是什么？

我试过这个以获得期初余额，但它看起来并不充足：

select balance from (select * from  client_balances where client_number = '7734766688' 
order by TRAN_DATE asc) 
where TRAN_DATE >= '01-AUG-2014' and rownum =1;

请帮助，我被卡住了。

Answer 1

with client_balances as (
select '7734766688' client_number, 23000 balance, to_date('07-08-2014', 'DD-MM-YYYY') tran_date from dual
union all select '7734766688', 40000, to_date('07-08-2014', 'DD-MM-YYYY') from dual
union all select '7734766688', 20000, to_date('10-08-2014', 'DD-MM-YYYY') from dual
union all select '7734766688', 13000, to_date('15-08-2014', 'DD-MM-YYYY') from dual
union all select '7734766688', 400000, to_date('29-08-2014', 'DD-MM-YYYY') from dual
union all select '7734766688', 200000, to_date('02-09-2014', 'DD-MM-YYYY') from dual
),
client_balances_analytic as (
select client_number, balance, tran_date, 
       lag(balance) over(partition by client_number order by tran_date) prev_balance,
       lag(tran_date) over(partition by client_number order by tran_date) prev_tran_date
from client_balances)
select tran_date_start, balance_start, tran_date_end, balance_end from (
  select case when tran_date = to_date('12-08-2014', 'DD-MM-YYYY') then tran_date else nvl(prev_tran_date, tran_date) end tran_date_start, 
         case when tran_date = to_date('12-08-2014', 'DD-MM-YYYY') then balance else nvl(prev_balance, balance) end balance_start, 
         row_number() over(order by tran_date) rw,
         last_value(tran_date) over(order by tran_date rows between current row and unbounded following) tran_date_end,
         last_value(balance) over(order by tran_date rows between current row and unbounded following) balance_end
   from client_balances_analytic 
  where client_number = '7734766688' and tran_date between to_date('12-08-2014', 'DD-MM-YYYY') and to_date('31-08-2014', 'DD-MM-YYYY')
) where rw = 1;

滞后函数检索上一行的数据

此查询可能无法正常使用tie（相同的tran_dates）。在这种情况下，您需要一些额外的标准来对事务进行排序（以便最早获得）

从第一个日期和最后一个日期sql获取值

1 个答案: