Question

我有以下字典，即从XHR请求生成的json对象，其中字典键由元组组成：

{(u'goal', u'corner', u'rightfoot'): 1, (u'goal', u'openplay', u'rightfoot'): 3, (u'miss', 
    u'corner', u'header'): 8, (u'goal', u'corner', u'header'): 1, (u'goal', u'openplay', u'leftfoot'): 2,
     (u'miss', u'openplay', u'rightfoot'): 30, (u'miss', u'corner', u'rightfoot'): 2, (u'miss', 
    u'crossedfreekick', u'header'): 3, (u'goal', u'penalty', u'rightfoot'): 1, (u'miss', u'fastbreak', 
    u'rightfoot'): 2, (u'miss', u'crossedfreekick', u'rightfoot'): 3, (u'goal', u'openplay', u'header'): 
    1, (u'goal', u'crossedfreekick', u'rightfoot'): 1, (u'miss', u'openplay', u'header'): 2, (u'goal', 
    u'crossedfreekick', u'header'): 1, (u'miss', u'openplay', u'leftfoot'): 22, (u'miss', 
    u'directfreekick', u'rightfoot'): 1, (u'miss', u'crossedfreekick', u'leftfoot'): 1}

我使用以下代码来有条理地对上面的字典中的值求和：

goal1 = {"'goal','openplay','leftfoot'", "'goal','openplay','rightfoot'", "'goal','openplay','header'", "'goal','openplay','otherbodypart'"}
                            regex1 = sum(int(value) for key, value in regex if key in goal1)

但是，这会产生以下错误消息：

regex1 = sum(int(value) for key, value in regex if key in goal1)
    exceptions.ValueError: too many values to unpack

任何人都可以向我解释为什么这是和/或更正另一种语法？

由于

Answer 1

regex1 = sum(int(value) for key, value in regex.items() if key in goal1)

你需要使用包含键和值的dict.items，循环遍历regex dict，你只是在迭代密钥，因此你无法解包密钥和值，因此错误。< / p>

键也是元组，因此您需要将键存储为goal1中的元组：

goal1 = {('goal','openplay','leftfoot'), ('goal','openplay','rightfoot'), ('goal','openplay','header'), ('goal','openplay','otherbodypart')}


print(regex1)
6

为什么我收到错误'exceptions.ValueError：要解压的值太多'？

1 个答案: