Question

Chrome JavaScript API在各个地方使用match patterns。在Chrome扩展程序中，有没有办法手动调用Google用来测试URL是否遵循给定匹配模式的任何功能？我有一堆我想测试的网址。

Answer 1

不，没有。但是，使用正则表达式复制并不困难。

这是一个实现。它检查匹配模式的正常限制，但不检查主机模式/测试URL主机的有效性。

function patternToRegExp(pattern){
  if(pattern == "<all_urls>") return /^(?:http|https|file|ftp):\/\/.*/;

  var split = /^(\*|http|https|file|ftp):\/\/(.*)$/.exec(pattern);
  if(!split) throw Error("Invalid schema in " + pattern);
  var schema = split[1];
  var fullpath = split[2];

  var split = /^([^\/]*)\/(.*)$/.exec(fullpath);
  if(!split) throw Error("No path specified in " + pattern);
  var host = split[1];
  var path = split[2];

  // File 
  if(schema == "file" && host != "")
    throw Error("Non-empty host for file schema in " + pattern);

  if(schema != "file" && host == "")
    throw Error("No host specified in " + pattern);  

  if(!(/^(\*|\*\.[^*]+|[^*]*)$/.exec(host)))
    throw Error("Illegal wildcard in host in " + pattern);

  var reString = "^";
  reString += (schema == "*") ? "https*" : schema;
  reString += ":\\/\\/";
  // Not overly concerned with intricacies
  //   of domain name restrictions and IDN
  //   as we're not testing domain validity
  reString += host.replace(/\*\.?/, "[^\\/]*");
  reString += "(:\\d+)?";
  reString += "\\/";
  reString += path.replace("*", ".*");
  reString += "$";

  return RegExp(reString);
}

// Usage example
// Precompile the expression for performance reasons
var re = patternToRegExp("*://*.example.com/*.css");
// Test against it
re.test("http://example.com/"); // false
re.test("https://example.com/css/example.css"); // true
re.test("http://www.example.com/test.css"); // true

致电Google的＃34;匹配模式＆＃34; API？

1 个答案: