在Android中,如何同步播放同步录音?

时间:2014-10-17 04:15:54

标签: android audio synchronization media-player mediarecorder

我正在尝试编写一个功能,可以在后台播放乐器时录制用户的声音。

我已经相当成功地让2个MediaPlayers几乎在同一时间开始。使用Threads和CyclicBarrier,我已经能够在5毫秒内启动2个MediaPlayer,这听起来不错。

问题在于,每当我尝试同时启动MediaRecorder和MediaPlayer时,它们之间会有明显的延迟。这是有问题的,因为当我播放录制的音频和乐器时,它们彼此不同步,因为录制的时间与播放器不同。

这是我尝试用于记录器和播放器的功能和2个线程。我为这个长度道歉,但如果有人有任何更好的想法,我将非常感激:

private void onRecord(boolean start) {
    if (start) {
       final CyclicBarrier recordBarrier = new CyclicBarrier(2);
       final CyclicBarrier postrecordBarrier = new CyclicBarrier(2);
       Thread beatTask = new Thread(new RecordBeatPlayTask(recordBarrier, postrecordBarrier), "Thread 1");
       Thread recordTask = new Thread(new RecordVoiceRecordTask(recordBarrier, postrecordBarrier), "Thread 2");

       beatTask.start();
       recordTask.start();
    } 
    else {
            mRecorder.stop();
            mRecordBeatPlayer.stop();

            mRecorder.release();
            mRecorder = null;
            mRecordBeatPlayer.release();
            mRecordBeatPlayer = null;
    }
}

private static class RecordVoiceRecordTask implements Runnable {

    private CyclicBarrier barrier;
    private CyclicBarrier barrier2;

    public RecordVoiceRecordTask(CyclicBarrier barrier, CyclicBarrier barrier2) {
        this.barrier = barrier;
        this.barrier2 = barrier2;
    }

    public void run() {
        try {
            mRecorder = new MediaRecorder();
            mRecorder.setAudioSource(MediaRecorder.AudioSource.MIC);
            mRecorder.setOutputFormat(MediaRecorder.OutputFormat.MPEG_4);
            mRecorderPath = Environment.getExternalStorageDirectory().getAbsolutePath();
            mRecorderPath += "/HypeHopRecording.mp4";
            mRecorder.setOutputFile(mRecorderPath);
            mRecorder.setAudioEncoder(MediaRecorder.AudioEncoder.AAC);
            try {
                mRecorder.prepare();
            } catch (IOException e) {
                Log.e("Recorder failed", "prepare() failed");
            }
            barrier.await();
            mRecorder.start();
            barrier2.await();
            System.out.println(Thread.currentThread().getName() + " has crossed the barrier");
        } catch (InterruptedException ex) {
            Logger.getLogger(RecordActivity.class.getName()).log(Level.SEVERE, null, ex);
        } catch (BrokenBarrierException ex) {
            Logger.getLogger(RecordActivity.class.getName()).log(Level.SEVERE, null, ex);
        }
    }
}

private static class RecordBeatPlayTask implements Runnable {

    private CyclicBarrier barrier;
    private CyclicBarrier barrier2;

    public RecordBeatPlayTask(CyclicBarrier barrier, CyclicBarrier barrier2) {
        this.barrier = barrier;
        this.barrier2 = barrier2;
    }

    public void run() {
        try {
            mRecordBeatPlayer = new MediaPlayer();

            try {
                mRecordBeatPlayer.setDataSource(mBeatPath);
                mRecordBeatPlayer.prepare();
            } catch (IllegalArgumentException e) {
                e.printStackTrace();
            } catch (SecurityException e) {
                e.printStackTrace();
            } catch (IllegalStateException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            barrier.await();
            mRecordBeatPlayer.start();
            barrier2.await();
            System.out.println(Thread.currentThread().getName() + " has crossed the barrier");
        } catch (InterruptedException ex) {
            Logger.getLogger(RecordActivity.class.getName()).log(Level.SEVERE, null, ex);
        } catch (BrokenBarrierException ex) {
            Logger.getLogger(RecordActivity.class.getName()).log(Level.SEVERE, null, ex);
        }
    }
}

1 个答案:

答案 0 :(得分:0)

基本上,'mRecordBeatPlayer.start()'之间存在延迟,并且用户可以听到声音,您必须测试此延迟。