Question

当有人在标题中提交带标点符号的内容时，我需要一种方法来引发错误。我是初学者，所以我不太清楚该怎么做形式：

class NeededForm(forms.ModelForm):
    title = forms.CharField(max_length=120)
    likes = forms.IntegerField(widget=forms.HiddenInput(), initial=0)
    body = forms.CharField(min_length=50,widget = forms.Textarea)
    captcha = CaptchaField()

    def clean_title(self):
        data = self.cleaned_data['title']
        return data
    class Meta:
        model = Needed
        fields = ('title', 'body', 'likes')

观点：

def detail(request, needed_title_url):
    context = RequestContext(request)

    needed_name = needed_title_url.replace('_', ' ')
    context_dict = {'needed_name': needed_name}
    try:
        needed = Needed.objects.get(title=needed_name)
        context_dict['needed'] = needed
        print "True!"
    except:
        pass

    return render_to_response('needed.html', context_dict, context)

如果用户输入类似：I like chicken!的标题作为标题，那么我需要向用户显示错误。

Answer 1

我不完全确定会提出您的问题，但看起来您正在寻找的答案可能会包含在https://docs.djangoproject.com/en/1.6/ref/models/fields/#slugfield

中

SlugField 是 CharField ，它只能包含字母，数字，下划线和连字符（因此它理解 max_length ，...）

class NeededForm(forms.ModelForm):
    title = forms.SlugField(max_length=120)
    likes = forms.IntegerField(widget=forms.HiddenInput(), initial=0)
    body = forms.CharField(min_length=50,widget = forms.Textarea)
    captcha = CaptchaField()

我正在寻找更复杂的规则检查，请查看验证器页面https://docs.djangoproject.com/en/1.6/ref/validators/以及如何以https://docs.djangoproject.com/en/1.6/ref/forms/validation/#using-validators形式使用它提供的示例是解释 SlugField 实现。

希望它有所帮助！

Answer 2

尝试此解决方案，确保标题中的每个单词仅包含字母，数字，短划线和撇号：

import string

def clean_title(self):
    title = self.cleaned_data['title']
    if all(letter not in string.punctuation
             for word in title.split()
             for letter in word
             if letter not in ['-',"'"]):
        return title
    raise forms.ValidationError('Title cannot have punctuation')

当表单有标点符号django时引发错误

2 个答案: