Question

我有两个数组。第一个是包含290个日期的数组。第二个是有3个日期的数组。我尝试了很多东西而且没有用过。这是我的代码。

foreach ($this->routes as $index=>$route) {
 if ($route['dateendRoute'] == $date) {
    echo '<tr>';
    echo '<td>' . $date . '</td>';
    echo '<td>' . $route['dateendRoute'] . '</td>';
    echo '<td>' . $route['total_distance'] . '</td>';
    echo '<td>' . $route['total_distance'] . '</td>';
    echo '<tr>';
    unset($this->routes[$index]);
 } else {
    echo '<tr>';
    echo '<td>' . $date . '</td>';
    echo '<td colspan=3>no data</td>';
    echo '</tr>';
 }
}

这就是我收到的。

2014-01-09  2014-01-09  12.01   12.01
2014-01-09  no data
2014-01-09  no data
2014-01-10  no data
2014-01-10  2014-01-10  13.37   13.37
2014-01-10  no data
2014-01-11  no data
2014-01-11  no data
2014-01-11  no data
2014-01-12  no data
2014-01-12  no data
2014-01-12  no data
2014-01-13  no data
2014-01-13  no data
2014-01-13  no data
2014-01-14  no data
2014-01-14  no data
2014-01-14  2014-01-14  12.88   12.88
2014-01-15  no data
2014-01-15  no data
2014-01-15  no data

我想收到的是这个。

2014-01-09  2014-01-09  12.01   12.01
2014-01-10  2014-01-10  13.37   13.37
2014-01-11  no data
2014-01-12  no data
2014-01-13  no data
2014-01-14  2014-01-14  12.88   12.88
2014-01-15  no data

请帮助：）

Answer 1

you need to make your array with date key 
foreach ($this->routes as $index=>$route) {
 if ($route['dateendRoute'] == $date) {
     $array[$date]=$your_value_is_here;
 } else {
     $array[$date]=$date." There is no data available ";
 }
}

and then print your array respective with your view

Answer 2

我按如下方式创建了一个较小的数据集：

$dates = array(
    '2014-01-09',
    '2014-01-10',
    '2014-01-11',
);

$routes = array(
    array(
        'dateendRoute'=>'2014-01-10',
        'total_distance'=>'2',
    ),
);

然后我更新了你的功能如下：

foreach ($this->dates as $date) {
    $routeIndex = -1;

    for ($i = 0; $i < count($this->routes); $i++) {
        if ($this->routes[$i]['dateendRoute'] == $date) {
            $routeIndex = $i;
            break;
        }
    }

    echo '<tr>';
    echo '<td>' . $date . '</td>';
    if ($routeIndex != -1) {
        echo '<td>' . $this->routes[$routeIndex]['dateendRoute'] . '</td>';
        echo '<td>' . $this->routes[$routeIndex]['total_distance'] . '</td>';
        echo '<td>' . $this->routes[$routeIndex]['total_distance'] . '</td>';
    } else {
        echo '<td colspan=3>no data</td>';
    }
    echo '</tr>';
}

这产生了我认为你正在寻找的东西：

2014-01-09  no data
2014-01-10  2014-01-10  2   2
2014-01-11  no data

Answer 3

模拟数组

$dates = array('2014-01-09','2014-01-10','2014-01-11','2014-01-12','2014-01-13','2014-01-14','2014-01-15');
$routes = array(
  array('dateendRoute' => '2014-01-09', 'total_distance' => '1.1'),
  array('dateendRoute' => '2014-01-11', 'total_distance' => '2.2'),
  array('dateendRoute' => '2014-01-14', 'total_distance' => '3.3')
);

遍历每个日期

foreach($dates as $date) {
  //assume no matches found
  $no_match = TRUE;
  foreach ($routes as $index=>$route) {
    if ($route['dateendRoute'] == $date) {
      //match found so switch this variable
      $no_match = FALSE;
      echo '<tr>';
      echo '<td>' . $date . '</td>';
      echo '<td>' . $route['dateendRoute'] . '</td>';
      echo '<td>' . $route['total_distance'] . '</td>';
      echo '<td>' . $route['total_distance'] . '</td>';
      echo '</tr>';
    }
  }
  //check if match found after looping through routes array
  if($no_match) {
    echo '<tr>';
    echo '<td>' . $date . '</td>';
    echo '<td colspan=3>no data</td>';
    echo '</tr>';
  }
}

这将产生以下输出

2014-01-09  2014-01-09  1.1 1.1
2014-01-10  no data
2014-01-11  2014-01-11  2.2 2.2
2014-01-12  no data
2014-01-13  no data
2014-01-14  2014-01-14  3.3 3.3
2014-01-15  no data

如何循环两个数组，如果值相等，则回显一些不回应的东西

3 个答案: