Question

我的要求非常简单：遍历数组，使用对象确定所选对象，然后将其推入新数组，但是我不知道如何编写？

想要的结果如下：

[{
    key: 'name',
    name: "A",
  },
  {
    key: 'note',
    name: "C”,
  }
]

我的代码：

var data = [{
  "data": {
    "list": [{
      "name": "A",
      "key": "name",
    }, {
      "name": "B",
      "key": "title",
    }, {
      "name": "C",
      "key": "note",
    }, {
      "name": "D",
      "key": "desc",
    }],
    "show": [
      "title",
      "desc"
    ]
  }
}]

var arr = []
data[0].data.list.map(item => {
  data[0].data.show.forEach(prop => {
    if (prop !== item.key) {
      arr.push({
        key: item.key,
        name: item.name
      })
    }
  })
})

console.log(arr);

Answer 1

您可以检查键是否包含在app.post('/upload/file', upload.single('file'), (req, res) => { cloudconvert.createProcess( { inputformat: 'docx', outputformat: 'pdf' }, (err, process) => { if (err) { console.error(`CloudConvert Process creation failed: ${err}`) } else { process.start({ input: { s3: { accesskeyid: SPACES_ACCESS_KEY_ID, secretaccesskey: SPACES_SECRET_ACCESS_KEY, bucket: 'files' } }, file: req.file.key, outputformat: 'pdf', output: { s3: { accesskeyid: SPACES_ACCESS_KEY_ID, secretaccesskey: SPACES_SECRET_ACCESS_KEY, bucket: 'files' } } }, (err, process) => { if(err) return console.log(err.message) console.log('process', process) }) } } ) })属性中，然后按下对象。

show

var data = [{ data: { list: [{ name: "A", key: "name" }, { name: "B", key: "title" }, { name: "C", key: "note" }, { name: "D", key: "desc" }], show: ["title", "desc"] } }], 
    arr = [];

data[0].data.list.map(({ key, name }) => {
    if (!data[0].data.show.includes(key)) {
        arr.push({ key, name });
    }
});

console.log(arr);

Answer 2

尝试

let d=data[0].data;
let arr= d.list.filter(x=> !d.show.includes(x.key));

var data = [{
  "data": {
    "list": [{
      "name": "A",
      "key": "name",
    }, {
      "name": "B",
      "key": "title",
    }, {
      "name": "C",
      "key": "note",
    }, {
      "name": "D",
      "key": "desc",
    }],
    "show": [
      "title",
      "desc"
    ]
  }
}]

let d=data[0].data;
let arr= d.list.filter(x=> !d.show.includes(x.key));

console.log(arr);

Answer 3

 var data = [{
      "data": {
        "list": [{
          "name": "A",
          "key": "name",
        }, {
          "name": "B",
          "key": "title",
        }, {
          "name": "C",
          "key": "note",
        }, {
          "name": "D",
          "key": "desc",
        }],
        "show": [
          "title",
          "desc"
        ]
      }
    }]

    var arr = []    

    data[0].data.list.forEach(keyValue=> !data[0].data.show.includes(keyValue.key) ? arr.push(keyValue): null)
    console.log(arr);

Answer 4

var data = [{
  "data": {
    "list": [{
      "name": "A",
      "key": "name",
    }, {
      "name": "B",
      "key": "title",
    }, {
      "name": "C",
      "key": "note",
    }, {
      "name": "D",
      "key": "desc",
    }],
    "show": [
      "title",
      "desc"
    ]
  }
}]

var arr = data[0].data.list.filter(item => data[0].data.show.every(props => props !== item.key))

console.log(arr);

如果不等于值，如何遍历推数组？

4 个答案: