Question

是否可以像这样解组XML文件：

<company id="bh23" name="imob">
   <store>
      <store-info id="2392">
         <address>NYC</address>
         <name>Imob's NYC 5th</name>
      </store>
      <products>
         <product>
             <name>keyboard</keyboard>
             <price>2000</price>
         </product>
         <product>
             <name>mouse</keyboard>
             <price>1000</price>
         </product>
      </products>
   </store>
   <store />
</stores>

进入这样的类：

@XmlElementRoot(name = "company")
public class Company {

    @XmlAttribute (name = "id")
    String id;
    @XmlAttribute (name = "name")
    String name;
    @XmlElement (name = "store")
    List<Store>stores;

    //all the getters and setters
 }


 @XmlElementRoot (name = "store")
 public class Store {

      @XmlAttribute (name = "id")
      String id;
      @XmlElement (name = "address")
      String address;
      @XmlElement (name = "name")
      String name;
      @XmlElementWrapper (name = "products")
      @XmlElement (name = "product")
      List<Product>products;

      //all the getters and setters
  }

  public class main {
      public static void main (String args[]) {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(Company.class);  
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();  
            Company portfolio = (Company) jaxbUnmarshaller.unmarshal(new File(xmlUrlPath));
            System.out.println(portfolio.toString());
        } catch (JAXBException e) {
            e.printStackTrace();
        }
      }
   }

我正在尝试“跳过”或“跳转”名为“store-info”的节点，因为我不想创建另一个类只是为了保留商店的地址和名称，因为它会更简单“将“地址和名称”附加到“商店”类。当然，当我运行代码时，变量“address”，“id”和“name”变为null，只有产品列表才能正确解组。有没有办法跳过一个节点，将他们的字段合并到另一个类？我正在避免（出于“合法”目的）使用MOXy lib及其XPath注释。

Answer 1

您可以创建一个StAX过滤的XMLStreamReader并让JAXB解组以忽略一个或多个XML元素。

http://docs.oracle.com/javase/7/docs/api/javax/xml/stream/XMLInputFactory.html#createFilteredReader%28javax.xml.stream.XMLStreamReader,%20javax.xml.stream.StreamFilter%29

以下是我在回答类似问题时给出的完整示例的链接：

JAXB filtered parsing

在使用JAXB解组XML时跳过XML节点

1 个答案: