我正在尝试使用Python 3中的NumPy fromfile
从文件中读取一串字节。我的目标是将字节转换为普通的Python 3字符串。例如:
$ echo "1234" > t.txt
现在文件t.txt
包含4个字节的文本。然后:
import numpy as np
values=np.fromfile('t.txt',dtype='|S1',count=4)
print ("values={}".format(values))
values=np.fromfile('t.txt',dtype='|U1',count=4)
print ("values={}".format(values))
给出:
values=[b'1' b'2' b'3' b'4']
Traceback (most recent call last):
File "./t.py", line 12, in <module>
print ("values={}".format(values))
File "/home/hakon/.pyenv/versions/3.4.2/lib/python3.4/site-packages/numpy/core/numeric.py", line 1715, in array_str
return array2string(a, max_line_width, precision, suppress_small, ' ', "", str)
File "/home/hakon/.pyenv/versions/3.4.2/lib/python3.4/site-packages/numpy/core/arrayprint.py", line 454, in array2string
separator, prefix, formatter=formatter)
File "/home/hakon/.pyenv/versions/3.4.2/lib/python3.4/site-packages/numpy/core/arrayprint.py", line 328, in _array2string
_summaryEdgeItems, summary_insert)[:-1]
File "/home/hakon/.pyenv/versions/3.4.2/lib/python3.4/site-packages/numpy/core/arrayprint.py", line 500, in _formatArray
word = format_function(a[-1])
UnicodeDecodeError: 'utf-32-le' codec can't decode bytes in position 0-3: codepoint not in range(0x110000)
我想获得像values='1234'
这样的普通Python 3字符串。怎么办呢?
答案 0 :(得分:2)
您可以使用astype
将字节转换为str:
import numpy as np
values = np.fromfile('t.txt',dtype='|S1',count=4).astype('|U1')
print(values)
# ['1' '2' '3' '4']
print(values.view('|U4'))
# ['1234']
print(values.dtype)
# <U1
答案 1 :(得分:1)
我知道问题明确要求np.fromfile
,但为什么不直接使用内置文件界面?
f = open('t.txt', 'r')
values = f.read().rstrip('\n')
f.close()
注意:默认情况下,Python 3字符串是Unicode。