选择具有最低日期的值

时间:2014-10-14 08:45:06

标签: sql-server

我有桌费率

Key   Rate      Dt
1      2      201401
1      2      201402
1      3      201403
2      1      201308
2      2      201309 
2      1      201301

我想选择具有最低Dt的密钥和费率。

所以结果应该是这样的:

   Key   Rate      Dt
    1      2      201401
    2      1      201308

我试过了:

  

从Dt =的比率中选择Key,Rate,Dt(从Rates中选择MIN(dt)   按键分组)

但它没有选择特定键的最低日期......你能帮帮我吗? 谢谢

3 个答案:

答案 0 :(得分:1)

您可以使用CTE获取相关记录......

;
WITH    cteLowestDate
          AS ( SELECT   [Key]
                       ,Rate
                       ,Dt
                       ,ROW_NUMBER() OVER (PARTITION BY [Key] ORDER BY Dt) AS 'rownum'
               FROM     Rates
             )
    SELECT  [Key], Rate, Dt
    FROM    cteLowestDate
    WHERE   rownum = 1

我添加了SQL Fiddle

答案 1 :(得分:1)

SELECT KEY,
       Rate,
       Dt
FROM   (SELECT KEY,
               Min(dt) dt
        FROM   Rates
        GROUP  BY KEY) A
       JOIN Rates B
         ON A.KEY = B.KEY
            AND A.dt = B.dt 

答案 2 :(得分:0)

我认为你的意思是:

  SELECT
    yt.key,
    yt.rate,
    yt.dt
  FROM
    (
      SELECT
        key,
        MIN(dt) AS min_dt
      FROM
        rates
      GROUP BY
        key
     ) AS kmd
     INNER JOIN rates AS yt ON
       yt.key=kmd.key AND
       yt.dt=kmd.min_dt
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