Question

我想为我的spritekit游戏创建一个无尽的滚动背景，iT应该包含一两个图像，它们会重复自己？我找到了这些one和two示例，但它们都在obj中。 C.

我不知道如何在Swift中实现这一目标。是否可以手动设置速度？

Ps：我没有转换obj的技巧。 C进入swift（新手到Xcode dev。）

Answer 1

我找到了一种方法来做到这一点，不知怎的，我设法转换this obj。 C迅速

您必须公开声明这两个节点

let background1 = SKSpriteNode(imageNamed: "bg1")
let background2 = SKSpriteNode(imageNamed: "bg2")

在“didMoveToView”方法中

background1.anchorPoint = CGPointZero
background1.position = CGPointMake(0, 0)
background1.zPosition = -15
self.addChild(background1)

background2.anchorPoint = CGPointZero
background2.position = CGPointMake(0, background1.size.height - 1)
background2.zPosition = -15
self.addChild(background2)

在“覆盖功能更新（currentTime：CFTimeInterval）”方法中添加

background1.position = CGPointMake(background1.position.x, background1.position.y - 2)
background2.position = CGPointMake(background2.position.x, background2.position.y - 2)

            if(background1.position.y < -background1.size.height)
            {
                background1.position = CGPointMake(background2.position.x, background1.position.y + background2.size.height )
            }

            if(background2.position.y < -background2.size.height)
            {
                background2.position = CGPointMake(background1.position.x, background2.position.y + background1.size.height)

            }

我不知道这是否是最有效的方式。其他问题提到了For循环。但在我看来这更容易。

Answer 2

我知道这场比赛已经晚了，但我也发现了如何横向完成这项工作！

从Egghead的代码开始（出色的工作！）我修改了一些东西：

    let background1 = SKSpriteNode(imageNamed: "Street_Example")
    let background2 = SKSpriteNode(imageNamed: "Street_Example")

此外：

    background1.position = CGPoint(x: frame.size.width / 2, y:frame.size.height / 2)
    background1.size = CGSize(width: frame.width, height: frame.height)
    background1.anchorPoint = CGPointZero
    background1.position = CGPointMake(0, 0)
    background1.zPosition = -15
    self.addChild(background1)

    background2.size = CGSize(width: frame.width, height: frame.height)
    background2.anchorPoint = CGPointZero
    background2.position = CGPointMake(background1.size.width - 1,0)
    background2.zPosition = -15
    self.addChild(background2)

并更新背景位置：

    background1.position = CGPointMake(background1.position.x-2, background1.position.y)
    background2.position = CGPointMake(background2.position.x-2, background2.position.y)
    if(background1.position.x < -background1.size.width)
    {
      background1.position = CGPointMake(background1.position.x + background2.size.width , background2.position.y)
    }
    if(background2.position.x < -background2.size.width)
    {
      background2.position = CGPointMake(background2.position.x + background1.size.height, background1.position.y) 
    }

Answer 3

我为此做了一堂课。目前它是为Swift 5.0或4.2编写的，它支持顶部，底部，左侧和右侧方向。

检查一下，看看它是否对你有帮助，它被称为InfiniteScrollingBackground：https://github.com/ThiagoAM/InfiniteScrollingBackground

Answer 4

你不需要这一切。

只需将此函数与您声明的变量以及您在didMoveToView中使用的属性一起使用。

func backgroudScrollUpdate(){
    background1.position = CGPointMake(background1.position.x, background1.position.y - 1)
    background2.position = CGPointMake(background1.position.x, background2.position.y - 1)
    if background1.position.y == -UIScreen.mainScreen().bounds.height{
        background1.position = CGPointMake(0, 0)
        background2.position = CGPointMake(0, 0 + UIScreen.mainScreen().bounds.height)
    }
}

然后在你的更新方法中调用它。

当然，这不是最好的方式，因为当你有更多的循环时它可以读取两个图像。

Answer 5

我想出的是：

   func terrain() -> SKNode {
        let color = UIColor.init(red: randomColorChannel(), green: randomColorChannel(), blue: randomColorChannel(), alpha: 1.0)

        let scale: CGFloat = 1.0// UIScreen.mainScreen().scale
        let size = CGSizeMake(frame.size.width * scale, frame.size.height * scale)
        let node = SKSpriteNode.init(color: color, size: size)
        node.anchorPoint = CGPointZero
        node.position = CGPointMake(0, UIScreen.mainScreen().bounds.size.height)

        return node
    }

在更新中执行此操作：

override func update(currentTime: NSTimeInterval) {
        var newPosition1 = terrain1.position
        var newPosition2 = terrain2.position

        newPosition1.y -= terrainSpeed
        if newPosition1.y < 0 {
            newPosition2.y -= terrainSpeed
        }

        terrain1.position = newPosition1
        terrain2.position = newPosition2

        if terrain1.position.y <= -UIScreen.mainScreen().bounds.size.height {
            removeChildrenInArray([terrain1])
            terrain1 = terrain()
            addChild(terrain1)
        }

        if terrain2.position.y <= -UIScreen.mainScreen().bounds.size.height {
            removeChildrenInArray([terrain2])
            terrain2 = terrain()
            addChild(terrain2)
        }
    }

所以基本上，地形被放置在视图上方，然后它们开始向下移动，并在需要时被新的替换，以重复。

Answer 6

    func backgroudScrollUpdate(){
        BG .position = CGPoint(x: BG.position.x - 5, y: BG.position.y)
        BG2.position = CGPoint(x: BG2.position.x - 5, y: BG2.position.y)
        if BG2.position.x <= -self.frame.size.width {
            BG.position = CGPoint(x: self.frame.size.width, y: 0)
        }
        if BG.position.x <= -self.frame.size.width {
        BG2.position = CGPoint(x: self.frame.size.width, y: 0)
    }
}

-UPDATED FOR SWIFT 3.1 -

这是我一直用它来使它适用于Y轴只需将X位置的所有额外东西切换到Y位置

Spritekit游戏中无尽的滚动（重复）背景 - Swift

6 个答案: