Question

我有一个简单的函数，我从表单中传递名称和年龄参数。我调用外部方法来生成＆＃34; isReady＆＃34;结果，但是当我运行它时，＆＃34; isReady＆＃34;结果打印代码而不是所需的结果。这很简单，我不知道我错过了什么。

function getWho(name, age) {

    this.name = name;
    this.age = age;
    this.isReady = youngOrOld;

    return [this.name, this.age, this.isReady];

}

function youngOrOld() {
    var result;
    var yourAge = this.age;

    switch(yourAge) {
        case (yourAge < 13) :
        result = "You're just a babe";
        break;
        case (yourAge >= 13 && yourAge < 18):
            result = "You're in your teens";
            break;
        case (yourAge >= 18 && yourAge < 50):
            result = "You are an adult";
            break;
        case (yourAge >= 50):
            result = "You are a senior";
            break;
        default:
            result = "";
    }

    return result;
}

function getAgeResult(n, a) {

    var myArr = getWho(n, a);

    var myName = myArr[0].valueOf();
    var myAge = myArr[1].valueOf();
    var myResult = myArr[2].valueOf();

    document.getElementById("myDiv2").innerHTML = "Hello " + myName + ", you are " + myAge + " old and " + myResult;
}

结果如下：你好克里斯，你是23岁并且函数youngOrOld（）{var result; var yourAge = this.age; switch（yourAge）{case（yourAge＆lt; 13）：result =＆＃34;你只是一个宝贝＆＃34 ;;打破; case（yourAge＆gt; = 13＆amp;＆amp; yourAge＆lt; 18）：result =＆＃34;你已经十几岁了？＃34 ;;打破; case（yourAge＆gt; = 18＆amp;＆amp; yourAge＆lt; 50）：result =＆＃34;你是一个成年人＆＃34 ;;打破; case（yourAge＆gt; = 50）：result =＆＃34;你是大四学生＆＃34 ;;打破;默认值：result =＆＃34;＆＃34 ;;返回结果; }

Answer 1

因为youngOrOld是一个函数，当它被添加到字符串时，解释器调用toString方法返回整个函数代码。你必须执行功能才能获得结果。

这是更正后的代码：

function getWho(name, age) {

    this.name = name;
    this.age = age;
    this.isReady = youngOrOld;
    //if you execute it now youngOrOld will not recognize this.age

    return [this.name, this.age, this.isReady()];

}

多次访问javascript数组

1 个答案: